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anonymous

  • one year ago

What is the nth term of this sequence? 1/3, 1/2, 3/5, 2/3, 5/7 A.) n / n-2(n+3) B.) n / n+2 C.) n / 2n+1 D.) n+2 / N-1 Please help! Thank you<3 xoxo

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  1. anonymous
    • one year ago
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    Heeelp ;~; Pweeeeeezzzz.

  2. anonymous
    • one year ago
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    you can just plug in the sequence indices to each choice until you get one that matches. \(a_1=\dfrac{1}{3}\\a_2=\dfrac{1}{2}\\a_3=\dfrac{3}{5}\\....\)

  3. anonymous
    • one year ago
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    Let me try..

  4. TrojanPoem
    • one year ago
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    Use the arithmetic rule

  5. TrojanPoem
    • one year ago
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    r= 1/2 - 1/3 = 3/6 - 2/6 = 1/6 a (first in the sequence) = 1/3 nth term = a + r( n - 1) = 1/3 + 1/6 ( n -1)

  6. TrojanPoem
    • one year ago
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    Can you do it ? It's hard to do maths on screen.

  7. anonymous
    • one year ago
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    Waaaah.. ;~: I'm trying

  8. anonymous
    • one year ago
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    I want to say it's A ... But I'm probably wrong

  9. TrojanPoem
    • one year ago
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    The arithmetic sequence won't work we don't add the same number each time.

  10. TrojanPoem
    • one year ago
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    By the way, why don't you use the "dumbs way" ? Put 1 , 2, 3 ,4 the one which gives you the same numbers as the choices is the right one.

  11. TrojanPoem
    • one year ago
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    B

  12. anonymous
    • one year ago
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    It's funny how the "dumbs way" helped me hahaha... Thank you for you assistance, sir SmartyPants. :)) <3

  13. TrojanPoem
    • one year ago
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    Anytime.

  14. anonymous
    • one year ago
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    sorry, I couldn't remember the formulas for series/sequences lol

  15. TrojanPoem
    • one year ago
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    Me too I think it can be solved using |dw:1435676869007:dw|

  16. anonymous
    • one year ago
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    \(\huge \Sigma\)

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