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isolate y in the first equation
can you do that?
I don't think so... Am I rewriting the first equation?
ya you want y by itself
first add y to both sides
then subtract 3 from both sides
now plug in (5x-3) for y in the second equation
now try and solve for x
no, foil out 2(5x-3)
Wouldn't I have to do 2 times 5 then 2 times 3
2 times 5 plus 2 times -3
*2 times 5x
2 times 5x= 10x 2 times =3= -6
thats right, so we have -10x + 10x - 6 = -6
Simplify? Like break it down again
you want to get x by itself to solve it
Do you minus one of them on both sides
lets just look at the x's. what is -10x + 10x?
so what should be your answer?
no, how did you get -3? anyways, since the x's cancel out there can't be a solution to this system of eqaution
Ah okay >< sorry, thanks for your help!