Yelp!!!

- asib1214

Yelp!!!

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- schrodinger

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- rvc

@Michele_Laino

- rvc

what is your ans?

- Michele_Laino

since we have three complete cycles within 4.8 meters, then the wavelength is:
4.8/3=1.6 meters

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## More answers

- rvc

since we have 3 waves
so divide 4.8 by 3
because one wave is equal to wavelength

- rvc

lol
sorry i did not see your post @Michele_Laino

- Michele_Laino

no worries :) @rvc

- Michele_Laino

the requested velocity, is:
4.8/6=...meters/seconds

- Michele_Laino

period is T= 6 /3 =...second
frequency f= 1/T =... Hz

- Michele_Laino

if the velocity of our wave is unchanged, then we can apply this formula:
\[\Large \lambda f = v\]
from which we get:
\[\Large \lambda = \frac{v}{f} = \frac{{0.8}}{2} = ...meters\]

- asib1214

this is how i did it, i first took the inverse of the Ferquency.....F=1/T which agve me the period

- Michele_Laino

how did you get 14.5 meters/second

- Michele_Laino

v=traveled space/time interval= 4.8/6=0.8 m/second

- Michele_Laino

period is
T=6/3= 2 seconds

- Michele_Laino

I think taht:
since within 6 seconds we have three complete waves, then the period is:T=6/3= 2 seconds

- Michele_Laino

so the corresponding frequency is:
f=1/T= 1/2=0.5 Hertz

- asib1214

when solving for the very first question wavelength.

- asib1214

i mean second cuz time is given after the wavelength question :(

- asib1214

so do we assume we don't know the time while solving for wavelength

- Michele_Laino

as I wrote before, in the last part of the first question, we have to assume that the speed of our wave is the same as before, namely, it is 0.8 m/second

- asib1214

@rvc do i figure out the amplitude? Please help!!!

- asib1214

@Astrophysics

- asib1214

how do i figure out the amplitude? Please help!!!

- asib1214

the picture is at the top.

- Astrophysics

|dw:1435727528455:dw| you can find the amplitude using \[Amplitude = \frac{ Distance }{ Frequency }\]

- Astrophysics

They are related.

- Astrophysics

No, the amplitude here is measured in decibels here. I think you're just confusing it because of the formula/ units but not really sure about what this actually means.

- Astrophysics

\[\lambda = \frac{ v }{ f }\]

- asib1214

can you quickly guide me what to do Please?!?!?!?!

- Astrophysics

Slow down, ok so we have |dw:1435728513829:dw| so we have 3 complete cycles here, so our wavelength is 4.8/3

- Astrophysics

\[y = A \sin \omega t\] you can use this A here is the amplitude the omega is angular frequency and t is the time period.

- Astrophysics

\[\omega = f 2 \pi\]

- Astrophysics

It's one in the same, math and physics are interrelated...

- Astrophysics

Lol, no problem, it can get confusing I guess, but I think you just need a decent understanding of what everything means and you will get it, you can try khan academy they have some nice videos on such topics I'm sure

- rvc

i m extremely sorry @asib1214
i was away from the laptop for a long time.
Thanks @Astrophysics :)
Sorry once again :)

- rvc

Do you have the formula for amplitude?

- rvc

so use the formula :)

- rvc

The maximum displacement of the particle from the mean position is the amplitude.

- rvc

:/

- rvc

v=n lambda

- rvc

:)

- rvc

idk :(

- rvc

@welshfella please help us

- welshfella

i'll have to look later if you still need it gotta go right now

- welshfella

there are 3 complete waves in the diagram so one wavelength is 4.8 / 3 m

- welshfella

well the amplitude is the distance from the equilibrium point to the crest of the wave. I'm not sure if we have enough information ..

- welshfella

i'll have to check that out.

- welshfella

A = D/F where D is distance travelled by the wave / frequency F

- welshfella

I'm a bit rusty with this stuff.

- welshfella

yes i see hmmm

- welshfella

1.6 m is correct for the wavelength i'm sure of that

- welshfella

yea sorry my recall of this stuff is really hazy.
one website i visited gave the formula A = D / F so i guess its must be right

- welshfella

D is distance and F = freqency in cycles per second

- welshfella

yea sorry i cant be of more help. If i have the time i'll have to revise this stuff - I did it in Physics years back!!

- Michele_Laino

hint:
in order to find the amplitude, you have to measure the distances D and H as below:

##### 1 Attachment

- Michele_Laino

you have to measures the distances H adn D on your drawing, using a scale ruler, then you have to solve this proportion:
\[\Large D:4.8 = H:x\]
where x is the requested amplitude

- Michele_Laino

so we have:
\[\Large x = \frac{{4.8 \times H}}{D} = ...\]

- Michele_Laino

what is the distance D? Please measure it with a scale ruler

- Michele_Laino

how many cm is D?
how many cm is H?

- Michele_Laino

ok! and how many cm is D?

- Michele_Laino

ok! then if we apply our formula, we get:
\[\Large x = \frac{{4.8 \times H}}{D} = \frac{{4.8 \times 1}}{{10.5}} = ...meters\]

- Michele_Laino

what is x?

- Michele_Laino

That's right!
better is x=0.457 meters

- Michele_Laino

it is a proportion

- Michele_Laino

we have finished, since by means of that proportion, our amplitude, is 0.457 meters

- Michele_Laino

yes! I am sure.

- Michele_Laino

yes! since our procedure is correct!

- Michele_Laino

yes! that's right!

- Michele_Laino

thanks!

- rvc

Thanks @Michele_Laino

- Michele_Laino

:) @rvc

- asib1214

@Astrophysics
A tuning fork with a frequency of 420Hz emits sound with a wavelength of 0.82m in air. If the temperature of the air increases, what will happen to the wavelength and why?

- Astrophysics

http://www.sengpielaudio.com/calculator-speedsound.htm

- asib1214

i understand that the rectangular wave on the left has a positive displacement because it's above the equilibrium and the triangle trough has a negative displacement, the thing that i don't understand here is that, Why Triangle trough DOESN'T have any displacement?!?!?!?!

- Michele_Laino

1) we have a destructive interference when 2 signals overlap each other and they cancel out each other, namely during that overlapping we have no signal, for example the dark fringes in a interference pattern
2) we have a constructive interference, when 2 signals overlap each other and they reinforce each other, so during that overlapping we have a signal whose intensity is greater than each of both overlapped signal. For example the bright fringes in a interference pattern

- asib1214

i understand that when two waves interfere with each other, they form a constructive wave, and when two waves with opposite displacement destruct each other!!!

- Michele_Laino

a destructive interference occurs, when from the overlapping between 2 signals, the resultant signal has a little intensity, less than the intensities of each signal

- asib1214

When these weird shapes confuse me, like when a triangle interferes with a rectangle :( like how do you figure out if they are going to form a constructive or destructive waves :(

- Michele_Laino

since the phase shift between the rectangle signal and the triangle signal is 180 degree, namely those signals interfere, each other, with opposite phases

- Michele_Laino

you have to subtract the y-coordinates of the triangle signal, from the corresponding y-coordinate of the rectangle signal

- asib1214

oh so since the triangle is flipped to 180 degress, but still how do i know the resultant displacement or what shape will wave form during the collision??!!?1

- Michele_Laino

as I wrote before, you can get that shape if you subtract the y-coordinates of the triangle signal, from the corresponding y-coordinate of the rectangle signal

- asib1214

can you please draw a quick drawing?!?!!?!?? :(

- asib1214

please!?!?!?!?!?!!?!?

- Michele_Laino

|dw:1436132812859:dw|

- Michele_Laino

|dw:1436132987610:dw|

- asib1214

i'll do the next two question after this example, please check them for me, I Love You!!! :")

- Michele_Laino

then we have:
|dw:1436133042674:dw|

- asib1214

OMG i'm crying here, Thank you so much, please stick around, i'll do the next two questions on my own. Please check them for me!!!! Thank you!!!!

- asib1214

wait one quick question here. how do you know the amplitude is 5, can you just assume and make up your own numbers to figureout the resultant displacement.

- asib1214

i nother words, how do yo know what shape is bigger or smaller :(

- Michele_Laino

the amplitude A is given by this computation:
\[A = \frac{{\max value - \min value}}{2}\]

- asib1214

OMG i'm going to ask you a very sily question but how did you come up with 5?!?!?

- Michele_Laino

I chose those value arbitrarily

- Michele_Laino

values*

- asib1214

because the picture didn't give any numbers, so when i'm solving questions on my own, how do i assume the amplitude is 5 and 8 :(

- asib1214

oh okay, let me try the next two questions and i'll get back to you.....i hope you'll be here!!! :")

- Michele_Laino

no, you have to measure your numbers using a scale ruler

- asib1214

ok so in what units???? cm?

- Michele_Laino

yes!

- asib1214

ok Thanks you Soooooooooooooooooooooooooooooooooooooooooooooooo MCH!!!! :")

- asib1214

Love you forever!!! :")

- Michele_Laino

Thanks!

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