Yelp!!!

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  • rvc
  • rvc
what is your ans?
since we have three complete cycles within 4.8 meters, then the wavelength is: 4.8/3=1.6 meters

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  • rvc
since we have 3 waves so divide 4.8 by 3 because one wave is equal to wavelength
  • rvc
lol sorry i did not see your post @Michele_Laino
no worries :) @rvc
the requested velocity, is: 4.8/6=...meters/seconds
period is T= 6 /3 =...second frequency f= 1/T =... Hz
if the velocity of our wave is unchanged, then we can apply this formula: \[\Large \lambda f = v\] from which we get: \[\Large \lambda = \frac{v}{f} = \frac{{0.8}}{2} = ...meters\]
this is how i did it, i first took the inverse of the Ferquency.....F=1/T which agve me the period
how did you get 14.5 meters/second
v=traveled space/time interval= 4.8/6=0.8 m/second
period is T=6/3= 2 seconds
I think taht: since within 6 seconds we have three complete waves, then the period is:T=6/3= 2 seconds
so the corresponding frequency is: f=1/T= 1/2=0.5 Hertz
when solving for the very first question wavelength.
i mean second cuz time is given after the wavelength question :(
so do we assume we don't know the time while solving for wavelength
as I wrote before, in the last part of the first question, we have to assume that the speed of our wave is the same as before, namely, it is 0.8 m/second
@rvc do i figure out the amplitude? Please help!!!
how do i figure out the amplitude? Please help!!!
the picture is at the top.
|dw:1435727528455:dw| you can find the amplitude using \[Amplitude = \frac{ Distance }{ Frequency }\]
They are related.
No, the amplitude here is measured in decibels here. I think you're just confusing it because of the formula/ units but not really sure about what this actually means.
\[\lambda = \frac{ v }{ f }\]
can you quickly guide me what to do Please?!?!?!?!
Slow down, ok so we have |dw:1435728513829:dw| so we have 3 complete cycles here, so our wavelength is 4.8/3
\[y = A \sin \omega t\] you can use this A here is the amplitude the omega is angular frequency and t is the time period.
\[\omega = f 2 \pi\]
It's one in the same, math and physics are interrelated...
Lol, no problem, it can get confusing I guess, but I think you just need a decent understanding of what everything means and you will get it, you can try khan academy they have some nice videos on such topics I'm sure
  • rvc
i m extremely sorry @asib1214 i was away from the laptop for a long time. Thanks @Astrophysics :) Sorry once again :)
  • rvc
Do you have the formula for amplitude?
  • rvc
so use the formula :)
  • rvc
The maximum displacement of the particle from the mean position is the amplitude.
  • rvc
:/
  • rvc
v=n lambda
  • rvc
:)
  • rvc
idk :(
  • rvc
@welshfella please help us
i'll have to look later if you still need it gotta go right now
there are 3 complete waves in the diagram so one wavelength is 4.8 / 3 m
well the amplitude is the distance from the equilibrium point to the crest of the wave. I'm not sure if we have enough information ..
i'll have to check that out.
A = D/F where D is distance travelled by the wave / frequency F
I'm a bit rusty with this stuff.
yes i see hmmm
1.6 m is correct for the wavelength i'm sure of that
yea sorry my recall of this stuff is really hazy. one website i visited gave the formula A = D / F so i guess its must be right
D is distance and F = freqency in cycles per second
yea sorry i cant be of more help. If i have the time i'll have to revise this stuff - I did it in Physics years back!!
hint: in order to find the amplitude, you have to measure the distances D and H as below:
1 Attachment
you have to measures the distances H adn D on your drawing, using a scale ruler, then you have to solve this proportion: \[\Large D:4.8 = H:x\] where x is the requested amplitude
so we have: \[\Large x = \frac{{4.8 \times H}}{D} = ...\]
what is the distance D? Please measure it with a scale ruler
how many cm is D? how many cm is H?
ok! and how many cm is D?
ok! then if we apply our formula, we get: \[\Large x = \frac{{4.8 \times H}}{D} = \frac{{4.8 \times 1}}{{10.5}} = ...meters\]
what is x?
That's right! better is x=0.457 meters
it is a proportion
we have finished, since by means of that proportion, our amplitude, is 0.457 meters
yes! I am sure.
yes! since our procedure is correct!
yes! that's right!
thanks!
  • rvc
:) @rvc
@Astrophysics A tuning fork with a frequency of 420Hz emits sound with a wavelength of 0.82m in air. If the temperature of the air increases, what will happen to the wavelength and why?
http://www.sengpielaudio.com/calculator-speedsound.htm
i understand that the rectangular wave on the left has a positive displacement because it's above the equilibrium and the triangle trough has a negative displacement, the thing that i don't understand here is that, Why Triangle trough DOESN'T have any displacement?!?!?!?!
1) we have a destructive interference when 2 signals overlap each other and they cancel out each other, namely during that overlapping we have no signal, for example the dark fringes in a interference pattern 2) we have a constructive interference, when 2 signals overlap each other and they reinforce each other, so during that overlapping we have a signal whose intensity is greater than each of both overlapped signal. For example the bright fringes in a interference pattern
i understand that when two waves interfere with each other, they form a constructive wave, and when two waves with opposite displacement destruct each other!!!
a destructive interference occurs, when from the overlapping between 2 signals, the resultant signal has a little intensity, less than the intensities of each signal
When these weird shapes confuse me, like when a triangle interferes with a rectangle :( like how do you figure out if they are going to form a constructive or destructive waves :(
since the phase shift between the rectangle signal and the triangle signal is 180 degree, namely those signals interfere, each other, with opposite phases
you have to subtract the y-coordinates of the triangle signal, from the corresponding y-coordinate of the rectangle signal
oh so since the triangle is flipped to 180 degress, but still how do i know the resultant displacement or what shape will wave form during the collision??!!?1
as I wrote before, you can get that shape if you subtract the y-coordinates of the triangle signal, from the corresponding y-coordinate of the rectangle signal
can you please draw a quick drawing?!?!!?!?? :(
please!?!?!?!?!?!!?!?
|dw:1436132812859:dw|
|dw:1436132987610:dw|
i'll do the next two question after this example, please check them for me, I Love You!!! :")
then we have: |dw:1436133042674:dw|
OMG i'm crying here, Thank you so much, please stick around, i'll do the next two questions on my own. Please check them for me!!!! Thank you!!!!
wait one quick question here. how do you know the amplitude is 5, can you just assume and make up your own numbers to figureout the resultant displacement.
i nother words, how do yo know what shape is bigger or smaller :(
the amplitude A is given by this computation: \[A = \frac{{\max value - \min value}}{2}\]
OMG i'm going to ask you a very sily question but how did you come up with 5?!?!?
I chose those value arbitrarily
values*
because the picture didn't give any numbers, so when i'm solving questions on my own, how do i assume the amplitude is 5 and 8 :(
oh okay, let me try the next two questions and i'll get back to you.....i hope you'll be here!!! :")
no, you have to measure your numbers using a scale ruler
ok so in what units???? cm?
yes!
ok Thanks you Soooooooooooooooooooooooooooooooooooooooooooooooo MCH!!!! :")
Love you forever!!! :")
Thanks!

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