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asib1214
 one year ago
Yelp!!!
asib1214
 one year ago
Yelp!!!

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2since we have three complete cycles within 4.8 meters, then the wavelength is: 4.8/3=1.6 meters

rvc
 one year ago
Best ResponseYou've already chosen the best response.1since we have 3 waves so divide 4.8 by 3 because one wave is equal to wavelength

rvc
 one year ago
Best ResponseYou've already chosen the best response.1lol sorry i did not see your post @Michele_Laino

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2no worries :) @rvc

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2the requested velocity, is: 4.8/6=...meters/seconds

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2period is T= 6 /3 =...second frequency f= 1/T =... Hz

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2if the velocity of our wave is unchanged, then we can apply this formula: \[\Large \lambda f = v\] from which we get: \[\Large \lambda = \frac{v}{f} = \frac{{0.8}}{2} = ...meters\]

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0this is how i did it, i first took the inverse of the Ferquency.....F=1/T which agve me the period

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2how did you get 14.5 meters/second

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2v=traveled space/time interval= 4.8/6=0.8 m/second

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2period is T=6/3= 2 seconds

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I think taht: since within 6 seconds we have three complete waves, then the period is:T=6/3= 2 seconds

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2so the corresponding frequency is: f=1/T= 1/2=0.5 Hertz

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0when solving for the very first question wavelength.

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0i mean second cuz time is given after the wavelength question :(

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0so do we assume we don't know the time while solving for wavelength

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2as I wrote before, in the last part of the first question, we have to assume that the speed of our wave is the same as before, namely, it is 0.8 m/second

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0@rvc do i figure out the amplitude? Please help!!!

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0how do i figure out the amplitude? Please help!!!

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0the picture is at the top.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435727528455:dw you can find the amplitude using \[Amplitude = \frac{ Distance }{ Frequency }\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0They are related.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0No, the amplitude here is measured in decibels here. I think you're just confusing it because of the formula/ units but not really sure about what this actually means.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0\[\lambda = \frac{ v }{ f }\]

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0can you quickly guide me what to do Please?!?!?!?!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Slow down, ok so we have dw:1435728513829:dw so we have 3 complete cycles here, so our wavelength is 4.8/3

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0\[y = A \sin \omega t\] you can use this A here is the amplitude the omega is angular frequency and t is the time period.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0\[\omega = f 2 \pi\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0It's one in the same, math and physics are interrelated...

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Lol, no problem, it can get confusing I guess, but I think you just need a decent understanding of what everything means and you will get it, you can try khan academy they have some nice videos on such topics I'm sure

rvc
 one year ago
Best ResponseYou've already chosen the best response.1i m extremely sorry @asib1214 i was away from the laptop for a long time. Thanks @Astrophysics :) Sorry once again :)

rvc
 one year ago
Best ResponseYou've already chosen the best response.1Do you have the formula for amplitude?

rvc
 one year ago
Best ResponseYou've already chosen the best response.1The maximum displacement of the particle from the mean position is the amplitude.

rvc
 one year ago
Best ResponseYou've already chosen the best response.1@welshfella please help us

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0i'll have to look later if you still need it gotta go right now

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0there are 3 complete waves in the diagram so one wavelength is 4.8 / 3 m

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0well the amplitude is the distance from the equilibrium point to the crest of the wave. I'm not sure if we have enough information ..

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0i'll have to check that out.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0A = D/F where D is distance travelled by the wave / frequency F

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0I'm a bit rusty with this stuff.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.01.6 m is correct for the wavelength i'm sure of that

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0yea sorry my recall of this stuff is really hazy. one website i visited gave the formula A = D / F so i guess its must be right

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0D is distance and F = freqency in cycles per second

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0yea sorry i cant be of more help. If i have the time i'll have to revise this stuff  I did it in Physics years back!!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2hint: in order to find the amplitude, you have to measure the distances D and H as below:

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2you have to measures the distances H adn D on your drawing, using a scale ruler, then you have to solve this proportion: \[\Large D:4.8 = H:x\] where x is the requested amplitude

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2so we have: \[\Large x = \frac{{4.8 \times H}}{D} = ...\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2what is the distance D? Please measure it with a scale ruler

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2how many cm is D? how many cm is H?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok! and how many cm is D?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok! then if we apply our formula, we get: \[\Large x = \frac{{4.8 \times H}}{D} = \frac{{4.8 \times 1}}{{10.5}} = ...meters\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2That's right! better is x=0.457 meters

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2it is a proportion

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2we have finished, since by means of that proportion, our amplitude, is 0.457 meters

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2yes! since our procedure is correct!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2yes! that's right!

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0@Astrophysics A tuning fork with a frequency of 420Hz emits sound with a wavelength of 0.82m in air. If the temperature of the air increases, what will happen to the wavelength and why?

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0i understand that the rectangular wave on the left has a positive displacement because it's above the equilibrium and the triangle trough has a negative displacement, the thing that i don't understand here is that, Why Triangle trough DOESN'T have any displacement?!?!?!?!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.21) we have a destructive interference when 2 signals overlap each other and they cancel out each other, namely during that overlapping we have no signal, for example the dark fringes in a interference pattern 2) we have a constructive interference, when 2 signals overlap each other and they reinforce each other, so during that overlapping we have a signal whose intensity is greater than each of both overlapped signal. For example the bright fringes in a interference pattern

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0i understand that when two waves interfere with each other, they form a constructive wave, and when two waves with opposite displacement destruct each other!!!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2a destructive interference occurs, when from the overlapping between 2 signals, the resultant signal has a little intensity, less than the intensities of each signal

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0When these weird shapes confuse me, like when a triangle interferes with a rectangle :( like how do you figure out if they are going to form a constructive or destructive waves :(

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2since the phase shift between the rectangle signal and the triangle signal is 180 degree, namely those signals interfere, each other, with opposite phases

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2you have to subtract the ycoordinates of the triangle signal, from the corresponding ycoordinate of the rectangle signal

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0oh so since the triangle is flipped to 180 degress, but still how do i know the resultant displacement or what shape will wave form during the collision??!!?1

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2as I wrote before, you can get that shape if you subtract the ycoordinates of the triangle signal, from the corresponding ycoordinate of the rectangle signal

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0can you please draw a quick drawing?!?!!?!?? :(

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0please!?!?!?!?!?!!?!?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2dw:1436132812859:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2dw:1436132987610:dw

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0i'll do the next two question after this example, please check them for me, I Love You!!! :")

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2then we have: dw:1436133042674:dw

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0OMG i'm crying here, Thank you so much, please stick around, i'll do the next two questions on my own. Please check them for me!!!! Thank you!!!!

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0wait one quick question here. how do you know the amplitude is 5, can you just assume and make up your own numbers to figureout the resultant displacement.

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0i nother words, how do yo know what shape is bigger or smaller :(

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2the amplitude A is given by this computation: \[A = \frac{{\max value  \min value}}{2}\]

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0OMG i'm going to ask you a very sily question but how did you come up with 5?!?!?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I chose those value arbitrarily

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0because the picture didn't give any numbers, so when i'm solving questions on my own, how do i assume the amplitude is 5 and 8 :(

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0oh okay, let me try the next two questions and i'll get back to you.....i hope you'll be here!!! :")

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2no, you have to measure your numbers using a scale ruler

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0ok so in what units???? cm?

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0ok Thanks you Soooooooooooooooooooooooooooooooooooooooooooooooo MCH!!!! :")

asib1214
 one year ago
Best ResponseYou've already chosen the best response.0Love you forever!!! :")
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