anonymous
  • anonymous
A circle has its center at (−2, −3) and a radius of 3 units. What is the equation of the circle? (x + 2)2 + (y − 3)2 = 9 (x − 2)2 + (y − 3)2 = 3 (x + 2)2 + (y + 3)2 = 9 (x + 2)2 + (y + 3)2 = 3
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
so the formula will be (x-x1) + (y-y1) = r^2
welshfella
  • welshfella
general form is (x - a)^2 + (y - b)^2 = r^2 where (a,b////0 is the centre and r = radius
anonymous
  • anonymous
so first of all, the -2 would be your x1

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welshfella
  • welshfella
* (a,b) is the centre
anonymous
  • anonymous
making the first part (x+2)
anonymous
  • anonymous
so what would you think the second part would be?
anonymous
  • anonymous
oh i screwed up, the (x+2) would be squared too
welshfella
  • welshfella
( y - (-3))^2 = ?
welshfella
  • welshfella
what does a double negative give you?
anonymous
  • anonymous
and you have a radius of 3, so the number on the right side would be three squared
anonymous
  • anonymous
so what does that make?
anonymous
  • anonymous
A
anonymous
  • anonymous
close
anonymous
  • anonymous
remember that your y coordinate is at -3
anonymous
  • anonymous
and the formula suggests subtracting your y coordinate
anonymous
  • anonymous
so you're subtracting a negative
anonymous
  • anonymous
so c
anonymous
  • anonymous
yep!
anonymous
  • anonymous
thank you
anonymous
  • anonymous
np

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