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anonymous

  • one year ago

A circle has its center at (−2, −3) and a radius of 3 units. What is the equation of the circle? (x + 2)2 + (y − 3)2 = 9 (x − 2)2 + (y − 3)2 = 3 (x + 2)2 + (y + 3)2 = 9 (x + 2)2 + (y + 3)2 = 3

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  1. anonymous
    • one year ago
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    so the formula will be (x-x1) + (y-y1) = r^2

  2. welshfella
    • one year ago
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    general form is (x - a)^2 + (y - b)^2 = r^2 where (a,b////0 is the centre and r = radius

  3. anonymous
    • one year ago
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    so first of all, the -2 would be your x1

  4. welshfella
    • one year ago
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    * (a,b) is the centre

  5. anonymous
    • one year ago
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    making the first part (x+2)

  6. anonymous
    • one year ago
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    so what would you think the second part would be?

  7. anonymous
    • one year ago
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    oh i screwed up, the (x+2) would be squared too

  8. welshfella
    • one year ago
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    ( y - (-3))^2 = ?

  9. welshfella
    • one year ago
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    what does a double negative give you?

  10. anonymous
    • one year ago
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    and you have a radius of 3, so the number on the right side would be three squared

  11. anonymous
    • one year ago
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    so what does that make?

  12. anonymous
    • one year ago
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    A

  13. anonymous
    • one year ago
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    close

  14. anonymous
    • one year ago
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    remember that your y coordinate is at -3

  15. anonymous
    • one year ago
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    and the formula suggests subtracting your y coordinate

  16. anonymous
    • one year ago
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    so you're subtracting a negative

  17. anonymous
    • one year ago
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    so c

  18. anonymous
    • one year ago
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    yep!

  19. anonymous
    • one year ago
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    thank you

  20. anonymous
    • one year ago
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    np

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