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anonymous

  • one year ago

What statement correctly describes the key features of the graph of f(x) = 4(1/2)^(x + 1) − 3? Y-intercept of (0, −1), starts up on the left, gets closer to y = −3 on the right Y-intercept of (0, −1), starts down on the left, gets closer to y = −3 on the right Y-intercept of (0, 1), starts up on the left, gets closer to y = −3 on the right Y-intercept of (0, 1), starts down on the left, gets closer to y = −3 on the right

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  1. anonymous
    • one year ago
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    @Albany_Goon

  2. welshfella
    • one year ago
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    to work out the y intercept put x = 0 into f(x) and work it out

  3. welshfella
    • one year ago
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    = 4(1/2)^(0+1) - 3 = ?

  4. anonymous
    • one year ago
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    Okay did it now how do I solve?

  5. welshfella
    • one year ago
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    what value did you get ?

  6. welshfella
    • one year ago
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    = 4(1/2)^(0+1) - 3 = 2^1 - 3

  7. anonymous
    • one year ago
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    -1

  8. welshfella
    • one year ago
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    right

  9. anonymous
    • one year ago
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    Now what?

  10. welshfella
    • one year ago
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    so work out some values of f(x) for negative x's like x = -2 2 f(-2) = 4 (1/2)^(-2+1) - 3 = 4 / (1/2) -3 = 5 f(-3) = 4(1/2)^-2 - 3 = 4 / 1/4 - 3 = 13 so the left side of the curve will descend pretty steeply

  11. anonymous
    • one year ago
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    Oh okay so what's next?

  12. welshfella
    • one year ago
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    |dw:1435686232852:dw|

  13. anonymous
    • one year ago
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    So B

  14. welshfella
    • one year ago
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    for high values of x the curve will tend to approach -3 because 1/2 to a high power will approach zero and that leaved - 3

  15. welshfella
    • one year ago
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    i'm not sure - i thought it would be up on the left

  16. welshfella
    • one year ago
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    |dw:1435686456854:dw|

  17. anonymous
    • one year ago
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    So A or B?

  18. welshfella
    • one year ago
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    it starts at high value of f(x) on the left so i think it starts 'up on the left' what do you think?

  19. welshfella
    • one year ago
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    I would go for A

  20. anonymous
    • one year ago
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    A

  21. welshfella
    • one year ago
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    yeah

  22. anonymous
    • one year ago
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    if i tag u can u help me with two more?

  23. welshfella
    • one year ago
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    i cant at the moment. I have to go right now.

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