anonymous
  • anonymous
What exponential function is the best fit for the data in the table? x f(x) 3 10 4 16 5 28 f(x) = 3(2)^(x − 2) + 4 f(x) = 3(2)^(x − 2) − 4 f(x) = 1/3(2)^(x − 2) + 4 f(x) = 1/3(2)^(x− 2) − 4
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@sammixboo
sammixboo
  • sammixboo
Let's start with \(\tt \color{red}{f(x)=3(2)^{(x − 2)} + 4}\) We can plug in 3 for\(\tt \color{red}{x}\), and 10 for \(\tt \color{red}{f(x)}\), and see if the equation it true. \(\tt \color{red}{10=3(2)^{(3 − 2)} + 4}\) \(\leftarrow\) Is this true?
sammixboo
  • sammixboo
If you are unsure if it is true, we can work it out and see.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
10= 6^(1)+4 10= 6 + 4 10 = 10 YES
sammixboo
  • sammixboo
:) So your answer is A
anonymous
  • anonymous
Thank You Sammi you are really smart!
sammixboo
  • sammixboo
Make sure you do the exponent first when solving a problem. It was ok to do the multiplying first, but next time make sure to solve the numbers with the exponents
anonymous
  • anonymous
Okay will do!

Looking for something else?

Not the answer you are looking for? Search for more explanations.