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anonymous
 one year ago
A running track in the shape of an oval is shown. The ends of the track form semicircles.
What is the perimeter of the inside of the track?
(π = 3.14)
392.00 m
372.22 m
444.44 m
588.88 m
anonymous
 one year ago
A running track in the shape of an oval is shown. The ends of the track form semicircles. What is the perimeter of the inside of the track? (π = 3.14) 392.00 m 372.22 m 444.44 m 588.88 m

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0get the perimeter of the 2 semicircles add them up add the rectangle in the middle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do u know the answer i thought it was 372.22 but idk

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i did the work what u said but idk i have a feeling its eitheir that or 444.44

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the perimeter of a circle is \(2\pi r\) the perimeter of a semicircle is half that or \(\pi r\) we have 2 semi circles.dw:1435687589686:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0given that the whole side is 48, we want the radius which is half of that or 24 then we can get the perimeters semicircle 1: 24pi semicircle 2: 24pi never mind the rectangle area, I was mistaken

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I keep getting 450.72 hmm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do u think its 444.44

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh my bad, that's 46 meters

anonymous
 one year ago
Best ResponseYou've already chosen the best response.023pi+23pi+150+150=444.44
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