## anonymous one year ago A running track in the shape of an oval is shown. The ends of the track form semicircles. What is the perimeter of the inside of the track? (π = 3.14) 392.00 m 372.22 m 444.44 m 588.88 m

1. anonymous

2. anonymous

get the perimeter of the 2 semicircles add them up add the rectangle in the middle

3. anonymous

do u know the answer i thought it was 372.22 but idk

4. anonymous

how'd you get that?

5. anonymous

i did the work what u said but idk i have a feeling its eitheir that or 444.44

6. anonymous

so the perimeter of a circle is $$2\pi r$$ the perimeter of a semicircle is half that or $$\pi r$$ we have 2 semi circles.|dw:1435687589686:dw|

7. anonymous

Yeah

8. anonymous

given that the whole side is 48, we want the radius which is half of that or 24 then we can get the perimeters semicircle 1: 24pi semicircle 2: 24pi never mind the rectangle area, I was mistaken

9. anonymous

I keep getting 450.72 hmm

10. anonymous

do u think its 444.44

11. anonymous

oh my bad, that's 46 meters

12. anonymous

23pi+23pi+150+150=444.44