anonymous
  • anonymous
will fan n medal Only 21% of the candidates who apply for an MBA program in a university are called for an interview, and only 5% of those who are called for an interview are offered admission. If the name of a candidate is picked at random from the list of all applicants, what is the probability that the candidate will finally be offered admission? 11.11% 15.11% 1.05% 1.01% 10.01%
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
What do you think?
anonymous
  • anonymous
i have no idea tbh
anonymous
  • anonymous
21% is the same thing as 0.21 5% is the same thing as 0.05 Multiply 0.21 * 0.05

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More answers

anonymous
  • anonymous
i got 0.0105
anonymous
  • anonymous
move the decimal over two spots (shouldve learned that in your lesson)
anonymous
  • anonymous
thanx man
anonymous
  • anonymous
np
anonymous
  • anonymous
you have anymore questions?
anonymous
  • anonymous
ya my bad 4 the long reply @KakeFace
anonymous
  • anonymous
np
anonymous
  • anonymous
so anymore questions?
anonymous
  • anonymous
ya gmmie a min sever crashed lol
anonymous
  • anonymous
ok
anonymous
  • anonymous
An experiment consists of selecting a number at random between 0 and 9 inclusive, and a letter from the English alphabet. What is the size of the sample space of this experiment? 35 36 52 234 260 the answer is b right?
anonymous
  • anonymous
1 sec im working it out
anonymous
  • anonymous
ight
anonymous
  • anonymous
10 numbers to choose from, and 26 letters. This gives you a total of 10x26 pairs, or 260. If you pick 0 as a number, you have 26 letters to match: (0, a), (0, b), ..., (0, z) If you pick 1 as a number, there are still 26 letters to match: (1, a), (1, b), ..., (1, z) and so on.
anonymous
  • anonymous
but the answer is B.. no?
anonymous
  • anonymous
it is B
anonymous
  • anonymous
fashoo
anonymous
  • anonymous
any more questions?
anonymous
  • anonymous
yes please
anonymous
  • anonymous
ok throw them at me
anonymous
  • anonymous
The probabilities of the top-selling menu item of the family restaurants in four towns being vegetarian and different types of non-vegetarian sandwiches are given in the table. Town Vegetable Sandwich Non-vegetarian Chicken Sandwich Non-vegetarian Ham Sandwich Non-vegetarian Bacon Sandwich Non-vegetarian Tuna Sandwich Town 1 6.63% 5.42% 7.05% 6.19% 5.91% Town 2 6.84% 7.11% 6.89% 5.69% 6.58% Town 3 5.97% 6.63% 5.72% 5.86% 5.79% Town 4 6.54% 5.86% 6.24% 6.24% 6.33% Total 6.24% 5.77% 6.03% 5.92% 6.27%% If a family restaurant in Town 2 has a non-vegetarian sandwich as its top-selling menu item, what is the probability that it is a tuna sandwich? 21.7% 25.0% 27.4% 62.7% 65.8%
anonymous
  • anonymous
what o you think for the first one?
anonymous
  • anonymous
this 1 has me completly stuck 2
anonymous
  • anonymous
ok 1 sec
anonymous
  • anonymous
ight
anonymous
  • anonymous
You just add the percentages from all the towns under the ham sandwich and divide 6.24 from the number you get. But i still cant get the right answer
anonymous
  • anonymous
so should i wait
anonymous
  • anonymous
1 sec ima try to work it out again
anonymous
  • anonymous
ight
anonymous
  • anonymous
is there a graph or a table for the first one?... the way its set up like that is confusing
anonymous
  • anonymous
my bad didnt notive that let me get a sec stupid sever crashed again
anonymous
  • anonymous
ok
anonymous
  • anonymous
dam i think the severs might be down 4 2 day c u 2morrow sorry man
anonymous
  • anonymous
wait i might still be able to work it out

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