anonymous
  • anonymous
will medal also fan anyone who helps i have 2 questions
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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NathalyN
  • NathalyN
ok
anonymous
  • anonymous
what is \[3^{\frac{ 2 }{ 3 }}\]
anonymous
  • anonymous
cube root of nine square root of nine cube root of 3 square root of 3

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More answers

anonymous
  • anonymous
@NathalyN help
anonymous
  • anonymous
@amoodarya @Bird_113 @Cubi-Cal
NathalyN
  • NathalyN
its not 1 or 2
anonymous
  • anonymous
k by the way \[\frac{ 2 }{ 3 }\] is an exponent
NathalyN
  • NathalyN
√3 = ± 1.7320508
NathalyN
  • NathalyN
for ther 1 one
anonymous
  • anonymous
ok
NathalyN
  • NathalyN
2^3 = 8
anonymous
  • anonymous
does anyone else think its a
anonymous
  • anonymous
@Mehek14 help
anonymous
  • anonymous
@KakeFace
anonymous
  • anonymous
@Keigh2015 help
anonymous
  • anonymous
@Mehek14 @Keigh2015 @KakeFace
Mehek14
  • Mehek14
this is how you do it Example: \(z^\dfrac{5}{3} = 3\sqrt{z^5}\)
anonymous
  • anonymous
oh
Mehek14
  • Mehek14
so your denominator is 3 it goes outside the radical \[^3\sqrt{3^2}\]
Mehek14
  • Mehek14
and \(3^2=9\)
Mehek14
  • Mehek14
\[^3\sqrt{9}\]
Keigh2015
  • Keigh2015
Are they answered?
anonymous
  • anonymous
ok so \[\sqrt[2]{3^{3}}\]
anonymous
  • anonymous
i have one more
Mehek14
  • Mehek14
no the other way \[^3\sqrt{3^2}\]
anonymous
  • anonymous
correct steps to find the value of \[8^{\frac{ 1 }{ 3 }}\]?
anonymous
  • anonymous
ok
Mehek14
  • Mehek14
\[\sqrt[3]{8^1}\]
Mehek14
  • Mehek14
\(8^1=8\) \[\sqrt[3]{8}\]
Mehek14
  • Mehek14
now find the cube root of 8
anonymous
  • anonymous
ok
Mehek14
  • Mehek14
what do you get?
anonymous
  • anonymous
2
Mehek14
  • Mehek14
that's how you solve it \(\ddot\smile\)
anonymous
  • anonymous
thx
Mehek14
  • Mehek14
yw
anonymous
  • anonymous
fan me back?
anonymous
  • anonymous
@Mehek14 fan me back :)?
sammixboo
  • sammixboo
|dw:1435691105316:dw|

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