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anonymous

  • one year ago

City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was −3° C. What was the temperature of City A and City B on that day?

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  1. anonymous
    • one year ago
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    City A was 5° C, and City B was 4° C. City A was 3° C, and City B was −1° C. City A was 8° C, and City B was −3° C. City A was 5° C, and City B was −5° C

  2. anonymous
    • one year ago
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    would it be the second answer

  3. welshfella
    • one year ago
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    let temperature in CitY A be x and temperature in City B be y

  4. welshfella
    • one year ago
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    4x = 3x + 8 x - 2y = -3

  5. anonymous
    • one year ago
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    wait so why would it be 4x instead of 8x

  6. welshfella
    • one year ago
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    you can find which option is correct by plugging in the given values and see which ones fit

  7. welshfella
    • one year ago
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    4 times x = 4x

  8. welshfella
    • one year ago
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    four times the temperature of city A = 4 times x = 4x

  9. anonymous
    • one year ago
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    ok thank you that makes alot more sense

  10. welshfella
    • one year ago
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    you can solve the system of equations or as I said earlier you can plug in the values in the options to see which fit.

  11. anonymous
    • one year ago
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    ill plug in the values

  12. anonymous
    • one year ago
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    4(3)=3(3)+8

  13. welshfella
    • one year ago
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    first try x=5 and y = 4 4(5) = 3(4) + 8 20 = 12 + 8 - those fit

  14. welshfella
    • one year ago
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    now plug same values into x - 2y = -3

  15. anonymous
    • one year ago
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    ok gotcha

  16. anonymous
    • one year ago
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    (5)-2(4)=-3

  17. anonymous
    • one year ago
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    5-8=-3 -3=-3

  18. anonymous
    • one year ago
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    it works

  19. welshfella
    • one year ago
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    right

  20. anonymous
    • one year ago
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    thanks

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