anonymous
  • anonymous
City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was −3° C. What was the temperature of City A and City B on that day?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
City A was 5° C, and City B was 4° C. City A was 3° C, and City B was −1° C. City A was 8° C, and City B was −3° C. City A was 5° C, and City B was −5° C
anonymous
  • anonymous
would it be the second answer
welshfella
  • welshfella
let temperature in CitY A be x and temperature in City B be y

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welshfella
  • welshfella
4x = 3x + 8 x - 2y = -3
anonymous
  • anonymous
wait so why would it be 4x instead of 8x
welshfella
  • welshfella
you can find which option is correct by plugging in the given values and see which ones fit
welshfella
  • welshfella
4 times x = 4x
welshfella
  • welshfella
four times the temperature of city A = 4 times x = 4x
anonymous
  • anonymous
ok thank you that makes alot more sense
welshfella
  • welshfella
you can solve the system of equations or as I said earlier you can plug in the values in the options to see which fit.
anonymous
  • anonymous
ill plug in the values
anonymous
  • anonymous
4(3)=3(3)+8
welshfella
  • welshfella
first try x=5 and y = 4 4(5) = 3(4) + 8 20 = 12 + 8 - those fit
welshfella
  • welshfella
now plug same values into x - 2y = -3
anonymous
  • anonymous
ok gotcha
anonymous
  • anonymous
(5)-2(4)=-3
anonymous
  • anonymous
5-8=-3 -3=-3
anonymous
  • anonymous
it works
welshfella
  • welshfella
right
anonymous
  • anonymous
thanks

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