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- anonymous

City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was −3° C. What was the temperature of City A and City B on that day?

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- anonymous

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- anonymous

City A was 5° C, and City B was 4° C.
City A was 3° C, and City B was −1° C.
City A was 8° C, and City B was −3° C.
City A was 5° C, and City B was −5° C

- anonymous

would it be the second answer

- welshfella

let temperature in CitY A be x and temperature in City B be y

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- welshfella

4x = 3x + 8
x - 2y = -3

- anonymous

wait so why would it be 4x instead of 8x

- welshfella

you can find which option is correct by plugging in the given values and see which ones fit

- welshfella

4 times x = 4x

- welshfella

four times the temperature of city A = 4 times x = 4x

- anonymous

ok thank you that makes alot more sense

- welshfella

you can solve the system of equations or as I said earlier you can plug in the values in the options to see which fit.

- anonymous

ill plug in the values

- anonymous

4(3)=3(3)+8

- welshfella

first try x=5 and y = 4
4(5) = 3(4) + 8
20 = 12 + 8
- those fit

- welshfella

now plug same values into
x - 2y = -3

- anonymous

ok gotcha

- anonymous

(5)-2(4)=-3

- anonymous

5-8=-3
-3=-3

- anonymous

it works

- welshfella

right

- anonymous

thanks

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