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you need 2 female employees to make up the committee of 3. this = 5C2 - the number of combination of 2 in 5
y isnt it permutations? 4 x 3 x 1
can you calculate 5C2?
yes it's 10 but how come it's not permutations i thought the order matters here
the order doesn't matter in this case
yes 5*4 /2 = 10 is correct
y doesn't the order matter?
well Jane , Lois and Jack are the same committee as Lois, Jane and Jack
that-s a committee - 3 people the order they are picked doesn't matter
So you're saying that because the guy is gonna be in the committee anyway it doesn't matter?
is Jack, Lois and Jane a different committee to Lois Jane and Jack?
there you go then
still no clue
still think 4 x 3 x 1 is supposed to be right
why 4*3*1 ?
wait nvm i got it thanks
you can write all the different combinations of 2 from 5 if you like - the man is always there so if the females are a,b,c,d and e then combinations are ab ac ad ae bc bd be cd ce de which are 10