anonymous
  • anonymous
Which of the following is a solution of x2 - 7x = -5?
Mathematics
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anonymous
  • anonymous
Which of the following is a solution of x2 - 7x = -5?
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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pooja195
  • pooja195
Do the directions specify what method to use? Quadratic Formula ? Factoring?
anonymous
  • anonymous
quadratic formula
pooja195
  • pooja195
Ok can you put it into \[\huge~\rm~ax^2+bx+c=0 \] form?

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anonymous
  • anonymous
x^2 -7x+5=0 right?
pooja195
  • pooja195
yes now list your abc values
anonymous
  • anonymous
a=1 b=-7 c=5
pooja195
  • pooja195
Good \[\huge~\rm~~x=\frac{ -(-7)~\pm \sqrt{(-7)^2-4(1)(5)} }{ 2(1) }\] \[\huge~\rm~~x=\frac{ 7)~\pm \sqrt{(-7)^2-4(1)(5)} }{ 2(1) }\] simplify
anonymous
  • anonymous
a.7 plus or minus the square root of 69 divided by two b.7 plus or minus the square root of 29 divided by two. c.negative 7 plus or minus the square root of 29 divided by two d.negative 7 plus or minus the square root of 69 divided by two.
anonymous
  • anonymous
these are the answers i have and my answer doesnt match any of them
pooja195
  • pooja195
\[\huge~\rm~(−7)^2−4(1)(5)\] solve this part only
anonymous
  • anonymous
i got \[\frac{ 7\pm \sqrt{25} }{ 2}\]
anonymous
  • anonymous
ok now what?
pooja195
  • pooja195
that should have been 29
anonymous
  • anonymous
oh i got it i had to redo it and do it all together this time. so it would be \[\frac{ 7\pm \sqrt{29} }{ 2 }\]
pooja195
  • pooja195
\[\huge~\rm~ \frac{ 7\pm \sqrt{29} }{ 2}\]
pooja195
  • pooja195
yep :)
anonymous
  • anonymous
thank you
pooja195
  • pooja195
no problem :) \(\huge\color{orange}{Welcome~To~OpenStudy}\) Hey there!!! Since you are new here, read this legendary tutorial for new OpenStudiers!! http://goo.gl/5pp1u0 For an visual tutorial look at this! Its amazing :o https://prezi.com/fs3hqdpcopic/an-unofficial-guide-to-openstudy/ Also consider reading the CoC and the T&C http://openstudy.com/code-of-conduct http://openstudy.com/terms-and-conditions

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