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anonymous
 one year ago
I need someone to explain this to me
Let u = <5, 1>, v = <7, 4>. Find 9u  6v.
anonymous
 one year ago
I need someone to explain this to me Let u = <5, 1>, v = <7, 4>. Find 9u  6v.

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TheSmartOne
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf a <b,c>~ =~ <ab,ac>\)

TheSmartOne
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf y=~<a,b>\) \(\bf z=~<c,d>\) \(\bf yz =\) \(\sf <a,b>  <c,d>~= ~<a,b> <c,d>~=~<ac,~bd>\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay im even more confused

TheSmartOne
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf y=~<a,b>\) \(\bf z=~<c,d>\) \(\bf yz =\) \(\sf <a,b>  <c,d>~=~<ac,~bd>\) Oops, fixed the redundant error...

TheSmartOne
 one year ago
Best ResponseYou've already chosen the best response.1https://www.mathsisfun.com/algebra/vectors.html Review the topic :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could you possibly plug in the numbers for the Y & Z?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes i need an explanation, not symbols

TheSmartOne
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf u= ~<5,1>\) \(\bf 9u = 9<5,1>~= <9\times (5) , 9\times 1>\)

TheSmartOne
 one year ago
Best ResponseYou've already chosen the best response.1That's unfortunate, because we can't solve this without the vector symbol :p

TheSmartOne
 one year ago
Best ResponseYou've already chosen the best response.1so what is \(\sf 9\times (5) =?\) and \(\sf 9\times1 =?\)

TheSmartOne
 one year ago
Best ResponseYou've already chosen the best response.1correct, so now we have \(\bf 9u =~<45,9>\)
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