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chris215

  • one year ago

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  1. anonymous
    • one year ago
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    you can solve this using kinematics for an uniform acceleration: \(x=v_0t+\frac{1}{2}at^2\) the final position here is \(x=60m\) the values for acceleration and initial speed are also given in the problem...

  2. asib1214
    • one year ago
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    Given: average velocity= -7.5m/s/s, d=60m, initial velocity= 108km/h, final velocity=N/A, Time=? Always remember this rule, the variable NOT/ N/A given to you is the formula your gunna use to figure out time. In this case it's gunna be d=Vi X t + 1/2 average velocity X t^2. Solve for T and your good to go.

  3. Michele_Laino
    • one year ago
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    here we have to apply this equation: \[\Large 0 = {v_0} - at\] where t is the requested time, v_0=108 Km/hours= 30 meters/second, and a=7.5 meters/second

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