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i tried that and i wound up with \[\frac{ 6\pm \sqrt{-16} }{ -2}\]

\[\text{ dividing both sides by 5} \\ x^2+6x+13=0\]

just need to find sqrt(16) and just recall how we rename sqrt(-1)

how did you get -1 in radical and 16 ?

so 4? sqrt -1?

wait would it be d?

oh so A i got it ! lol

can you help me with this one as well ?
Solve -3x2 + 30x - 90 = 0.

try dividing both sides by -3
and use quadratic formula again

lol hold on a baby stole my pen and paper lol

oh no!

i got it back lol

ok

k im stuck on almost the last part im at \[\frac{ -10\pm \sqrt{220} }{ 2 }\]

let me check what you have so far
one sec

so -(-10)=10
and 100-120=-20

\[x=\frac{10 \pm \sqrt{-20}}{2}\]

\[x=\frac{10 \pm \sqrt{-1} \sqrt{4} \sqrt{5}}{2}\]
see if you can simplify from there

is it this?x equals 10 plus or minus 2i square root of 5

all over 2 right ?

huh?

\[x=\frac{ 10 \pm i (2)\sqrt{5}}{2}\]
you didn't say anything about the 2 on bottom

ohj yea

anyways you can separate the fraction and simplify a bit more

with the 10 and the 2?

(A+B)/C=A/C+B/C
so from previous we have:
\[x=\frac{10}{2} \pm i \frac{2}{2}\sqrt{5}\]

x equals 5 plus or minus i square root of 5?

yes since 10/2=5 and 2/2=1

can you help me with the rest xDDD lol

Solve 5x2 = -30x - 65.

that is the same as the first equation you put

but we can do it again if you didn't understand it

oh lol i put the wrong one cx

Solve x2 + 4x + 8 = 0.

you can skip to comparing your equation to ax^2+bx+c=0

which I think your problem isn't identifying a,b, and c

your problem is playing with the square root and separating the fraction

\[\frac{ -4\pm \sqrt{16-32} }{ 2 }\]
so \[\frac{ -4\pm \sqrt{-16} }{ 2 }\]
but im stuck now :/

beautiful so far

I actually simplify sqrt(-16) for you above

would i divide the -16 by 4?

so would it be x equals negative 4 plus or minus 2 I

all over ?

oh wait and why 2?

sqrt(16)=4 not 2

cause it was all over two

minus what i said

so \[-2\pm2i\]

yes

since -4/2=-2
and 4/2=2
so yep
\[x=\frac{-4}{2} \pm \frac{4}{2}i =-2 \pm 2i\]

with peterpan
remember those kids never get pizza

that is true but i would find a way to create it xD

thank you again!!

np :)