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anonymous
 one year ago
Help pleaseeeeeeeeeeee =*(
anonymous
 one year ago
Help pleaseeeeeeeeeeee =*(

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435701198421:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{\sqrt{\sqrt{3x}}}=\sqrt[6]{3x}\]\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0think that should be a 8 not 6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you have \[\sqrt[8]{3x}=\sqrt[4]{2x}\] raise each side to the power of 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah you are right it should be \(\sqrt[8]{2x}\) raise each side to the power of 8 to clear the radicals

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[3x=4x^2\] is what you will get then solve for \(x\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hey how did u get that....?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0raised both sides to the power of 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt[8]{3x}^8=3x\] \[\sqrt[4]{2x}^8=(2x)^2=4x^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why? to get rid of the radicals

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but i don't understand why when the base is different numbers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if you want to get rid of the racial on \(\sqrt[8]{3x}\) it should be pretty clear you have to raise it to the power of 8 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i don't understand that part is that like a rule or something?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when r u allowed to do that? when they're both divisible by the same number?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how else can you do it? you have the eighth root if you want to get it without the eighth root you have to raise it to the power of 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what else can you do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you just come up with the 8 out of thin air? there isn't a rule or anything?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no , it was the eighth root if it was the fifteenth root, you would have to do something different

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0.... omg im so lost and nervous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm seriously not understanding that part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how are you going to get the \(3x\) outside of the radical ? you have \[\sqrt[8]{3x}\] what can you do to get rid of that radical?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if you square it, you would still have a radical wouldn't you ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435702119282:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually \(\left(3x\right)^{\frac{1}{8}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so how come u get rid of that one but not the right side with the 2x? how come it gets neglected?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh don't neglect it , it will feel left out if you raise the left hand side to the power or 8 you have to do the same thing to the right hand side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes but the right still has a power of 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt[4]{2x}^8=(2x)^2=4x^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i thought we're trying to eliminate the power

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can't always get what you want you gotta use what you got

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok... i think i get it.... so what if the right side is not divisible by the number it's divided by on the right side?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0on the left side no the rights *

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is an excellent question, best one yet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then i guess you would have to multiply by the least common multiple of the indices

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ... i'm sorry to be so bothersome but can u please give me n example ? i just really wanna get this question and prepare for future problems like this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so if you had, for example \[\sqrt[4]{3x}=\sqrt[6]{2x}\] you would have to raise each side to the power of 12 since the least common multiple of 4 and 6 is 12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then both radicals would be gone and you would ge t \[(3x)^3=(2x)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the objective is to get rid of the fraction power right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just so happens in this case raising to the power of 8 gets rid of the radical on both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ahhhhhhhhhhhhhhhhhhhh i got it!!!!!!! thank you <333333333333333

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0btw you still have to solve \[3x=4x^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got the answer i just needed to know how to do it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0one answer is obviously 0 the other you get from solving \[4x^2x=0\] etc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey wait one more question.. if the problem was reversed it doesn't matter right? like the 3x was on the right side and the 2x was on the left as long as one of fractions is gone that's the objective no matter the left or right side right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah that has nothing to do with it of course the answer would be different, but the method would be the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay gotcha thank you again <333
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