A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Help pleaseeeeeeeeeeee =*(

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1435701198421:dw|

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\sqrt{\sqrt{\sqrt{3x}}}=\sqrt[6]{3x}\]\]

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    think that should be a 8 not 6

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so you have \[\sqrt[8]{3x}=\sqrt[4]{2x}\] raise each side to the power of 8

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah you are right it should be \(\sqrt[8]{2x}\) raise each side to the power of 8 to clear the radicals

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[3x=4x^2\] is what you will get then solve for \(x\)

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hey how did u get that....?

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    raised both sides to the power of 8

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    wait what? why?

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\sqrt[8]{3x}^8=3x\] \[\sqrt[4]{2x}^8=(2x)^2=4x^2\]

  12. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why? to get rid of the radicals

  13. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but i don't understand why when the base is different numbers

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    if you want to get rid of the racial on \(\sqrt[8]{3x}\) it should be pretty clear you have to raise it to the power of 8 right?

  15. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lol "radical"

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no i don't understand that part is that like a rule or something?

  17. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    when r u allowed to do that? when they're both divisible by the same number?

  18. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how else can you do it? you have the eighth root if you want to get it without the eighth root you have to raise it to the power of 8

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what else can you do?

  20. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so you just come up with the 8 out of thin air? there isn't a rule or anything?

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no , it was the eighth root if it was the fifteenth root, you would have to do something different

  22. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    .... omg im so lost and nervous

  23. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm seriously not understanding that part

  24. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how are you going to get the \(3x\) outside of the radical ? you have \[\sqrt[8]{3x}\] what can you do to get rid of that radical?

  25. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    if you square it, you would still have a radical wouldn't you ?

  26. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1435702119282:dw|

  27. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    actually \(\left(3x\right)^{\frac{1}{8}}\)

  28. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay so how come u get rid of that one but not the right side with the 2x? how come it gets neglected?

  29. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh don't neglect it , it will feel left out if you raise the left hand side to the power or 8 you have to do the same thing to the right hand side

  30. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes but the right still has a power of 2

  31. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\sqrt[4]{2x}^8=(2x)^2=4x^2\]

  32. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i thought we're trying to eliminate the power

  33. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you can't always get what you want you gotta use what you got

  34. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oops \[3x=4x^2\]

  35. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok... i think i get it.... so what if the right side is not divisible by the number it's divided by on the right side?

  36. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    on the left side no the rights *

  37. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that is an excellent question, best one yet

  38. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then i guess you would have to multiply by the least common multiple of the indices

  39. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh ... i'm sorry to be so bothersome but can u please give me n example ? i just really wanna get this question and prepare for future problems like this

  40. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so if you had, for example \[\sqrt[4]{3x}=\sqrt[6]{2x}\] you would have to raise each side to the power of 12 since the least common multiple of 4 and 6 is 12

  41. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then both radicals would be gone and you would ge t \[(3x)^3=(2x)^2\]

  42. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ohhhhh hmmmmm

  43. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so the objective is to get rid of the fraction power right?

  44. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    just so happens in this case raising to the power of 8 gets rid of the radical on both sides

  45. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  46. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ahhhhhhhhhhhhhhhhhhhh i got it!!!!!!! thank you <333333333333333

  47. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yw

  48. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    btw you still have to solve \[3x=4x^2\]

  49. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i got the answer i just needed to know how to do it

  50. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    one answer is obviously 0 the other you get from solving \[4x^2-x=0\] etc

  51. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oops \[4x^2-3x=0\]

  52. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    3/4 = .75

  53. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  54. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Hey wait one more question.. if the problem was reversed it doesn't matter right? like the 3x was on the right side and the 2x was on the left as long as one of fractions is gone that's the objective no matter the left or right side right?

  55. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah that has nothing to do with it of course the answer would be different, but the method would be the same

  56. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay gotcha thank you again <333

  57. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.