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@ganeshie8 can u please help me?
Sorry I am checking other question so mixing up. give me a second.
hmm is "b" meant to be on a tangential line?
that is |dw:1435704514383:dw|
so... got any ideas on what "a" is?
something tells me is not a tangent :/
ok hmmm http://jwilson.coe.uga.edu/emt668/EMAT6680.2003.fall/Nichols/6690/Webpage/Day%204_files/image016.gif <--- notice that "inscribed angle and intercepted arc" theorem what do you think "a" is?
let us assume that line is a tangent
notice, that theorem plainly says the inscribed angle, is HALF of the intercepted arc
i cant figure out how exactly to find it.. do i need a to find b?
so.... using that... what would we get for "a"?
55? well.. how did you get 55 then?
isnt it half of 110?
well.. how does 110 come in?
idk i thought thats what u were talking about.. im confused
notice the "intercepted arc" from the "inscribed angle" \(\measuredangle a\)
so.. that makes "a" = ?
@jdoe0001 this one
hmm ahemm nope check the "intercepted arc and inscribed angle" theorem "a" is inscribed and is intercepting an arc that is 90 degrees... thus angle "a" is ?
i looked up inscribed angle thereom: The inscribed angle theorem states that an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle. Therefore, the angle does not change as its vertex is moved to different positions on the circle.
and so... "a" gives us?
"a" is half of the intercepted arc, so yes the arc is 90, the angle is half that, or 45 so hmmm one sec
anyway so using another theorem of a tangent hitting a chord |dw:1435707709250:dw|
gimme another sec =)
45*1/2= 22 1/2
im petty sure its 90
hmmm so |dw:1435708204884:dw|
so... what do you think b =? then
Im confused but i think b is 90
how is the other side 250?
well... hmm lemme put it this way |dw:1435708342095:dw|
because, one "arc" is already 110 a circle only has 360 degrees if one arc is taking up 110 its "counterpart" is taking up the rest
yeah i know the circle adds up to 360 degrees...
so.... that makes the other arc 250 degrees :)
yeah but i need to find B
so.. if that arc is 250 degrees, what do you think is the angle there, hitting the tangent and the chord?
if 250+110= 360 hows there another angle left? it only goes to 360 so im still lost
well u said a = 45
notice, that angle is really b+a so...we know the arc on that end is 250 degrees so that makes that angle, the angle b+a equals to?
r u saying b+a=250?
hmm you're mixing up ... angles and arcs nope, the arc is 250, the angle we dunno
well i dont get it.
well. that's the "central angle" for the intercepted arc for inscribed angle "a", yes
none of them add up
let us take what we know |dw:1435708854378:dw|
so.. hmm let us take so far what we know... so...the inscribed angle "a" is half the intercepted arc, so.... half 90, right?
ok so |dw:1435709025266:dw|
am i supposed to split 110 in half?
55? notice, 110 is taking one side of the circle and the OTHER arc, is taking up the REST of the circle if it were 55, then the circle would be 55+110 degrees
well u said its 110+250.....
I have to go bye
the other arc is 250 because a circle has 360 degrees 360 - 100 the rest is 250 degrees thus |dw:1435709354485:dw| keep in mind that |dw:1435709389265:dw|
i figured out the answer from somebody else.. Thank u for trying to help