## baby456 one year ago hey please help foe easy medal +fan square root of 9/16 +5

1. anonymous

??

2. anonymous

$\sqrt{\frac{9}{16}} +5$ like that?

3. baby456

yes

4. anonymous

what is $$\sqrt{9}$$?

5. baby456

3

6. anonymous

right !

7. anonymous

and what is $$\sqrt{16}$$?

8. triciaal

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9. baby456

is it rounded to 3/4

10. anonymous

no dear it is not "rounded" it is exactly $$\frac{3}{4}$$

11. triciaal

@satellite73 not your fan use both values

12. anonymous

$\huge \sqrt{\frac{9}{16}}=\frac{\sqrt{9}}{\sqrt{16}}=\frac{3}{4}$

13. baby456

ok thanks

14. anonymous

15. anonymous

what the monkey does "use both values" mean?

16. triciaal

when you take the square root -3/4 and +3/4

17. triciaal

negative * negative = positive and positive * positive = positive

18. anonymous

???

19. myininaya

sqrt(9/16) is the principal square root of 9/16 it is only the positive (or 0 if we have sqrt(0)) square root

20. triciaal

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21. anonymous

really? i guess all this time the square root is not a well defined function. who knew?

22. myininaya

$\sqrt{4}=2 \\ \text{ and if you had } \\ -\sqrt{4}=-(2)=-2$ but $\sqrt{4} \neq -2$

23. anonymous

elementary logic here $x^2=4\implies x=2\text{ or } x=-2$ but $$\sqrt{4}$$ is not some number whose square is 4, it is the positive number whose square is 4 you might have seen, for example, the $$\pm$$ in the quadratic formula

24. myininaya

let me resay this: the square root of 4 is 2 or -2 but $\sqrt{4}=2 \text{ and } \neq -2 \\ \text{ this is because we are suppose to read } \sqrt{ \cdot } \text{ as the princiapl square root }$

25. anonymous

if you have a choice, you would not need to write $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ you could omit the $$\pm$$ since apparently $$\sqrt{b^2-4ac}$$ can be positive or negative

26. Loser66

Like this sentence "what the monkey does "use both values" mean?" hahahaha............