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baby456
 one year ago
hey please help foe easy medal +fan square root of 9/16 +5
baby456
 one year ago
hey please help foe easy medal +fan square root of 9/16 +5

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{\frac{9}{16}} +5\] like that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what is \(\sqrt{9}\)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and what is \(\sqrt{16}\)?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435706759551:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no dear it is not "rounded" it is exactly \(\frac{3}{4}\)

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 not your fan use both values

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge \sqrt{\frac{9}{16}}=\frac{\sqrt{9}}{\sqrt{16}}=\frac{3}{4}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what the monkey does "use both values" mean?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0when you take the square root 3/4 and +3/4

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0negative * negative = positive and positive * positive = positive

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0sqrt(9/16) is the principal square root of 9/16 it is only the positive (or 0 if we have sqrt(0)) square root

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435707126496:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0really? i guess all this time the square root is not a well defined function. who knew?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{4}=2 \\ \text{ and if you had } \\ \sqrt{4}=(2)=2\] but \[\sqrt{4} \neq 2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0elementary logic here \[x^2=4\implies x=2\text{ or } x=2\] but \(\sqrt{4}\) is not some number whose square is 4, it is the positive number whose square is 4 you might have seen, for example, the \(\pm\) in the quadratic formula

myininaya
 one year ago
Best ResponseYou've already chosen the best response.0let me resay this: the square root of 4 is 2 or 2 but \[\sqrt{4}=2 \text{ and } \neq 2 \\ \text{ this is because we are suppose to read } \sqrt{ \cdot } \text{ as the princiapl square root }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if you have a choice, you would not need to write \[\frac{b\pm\sqrt{b^24ac}}{2a}\] you could omit the \(\pm\) since apparently \(\sqrt{b^24ac}\) can be positive or negative

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Like this sentence "what the monkey does "use both values" mean?" hahahaha............
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