baby456
  • baby456
hey please help foe easy medal +fan square root of 9/16 +5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
??
anonymous
  • anonymous
\[\sqrt{\frac{9}{16}} +5\] like that?
baby456
  • baby456
yes

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anonymous
  • anonymous
what is \(\sqrt{9}\)?
baby456
  • baby456
3
anonymous
  • anonymous
right !
anonymous
  • anonymous
and what is \(\sqrt{16}\)?
triciaal
  • triciaal
|dw:1435706759551:dw|
baby456
  • baby456
is it rounded to 3/4
anonymous
  • anonymous
no dear it is not "rounded" it is exactly \(\frac{3}{4}\)
triciaal
  • triciaal
@satellite73 not your fan use both values
anonymous
  • anonymous
\[\huge \sqrt{\frac{9}{16}}=\frac{\sqrt{9}}{\sqrt{16}}=\frac{3}{4}\]
baby456
  • baby456
ok thanks
anonymous
  • anonymous
then add 5 i guess
anonymous
  • anonymous
what the monkey does "use both values" mean?
triciaal
  • triciaal
when you take the square root -3/4 and +3/4
triciaal
  • triciaal
negative * negative = positive and positive * positive = positive
anonymous
  • anonymous
???
myininaya
  • myininaya
sqrt(9/16) is the principal square root of 9/16 it is only the positive (or 0 if we have sqrt(0)) square root
triciaal
  • triciaal
|dw:1435707126496:dw|
anonymous
  • anonymous
really? i guess all this time the square root is not a well defined function. who knew?
myininaya
  • myininaya
\[\sqrt{4}=2 \\ \text{ and if you had } \\ -\sqrt{4}=-(2)=-2\] but \[\sqrt{4} \neq -2\]
anonymous
  • anonymous
elementary logic here \[x^2=4\implies x=2\text{ or } x=-2\] but \(\sqrt{4}\) is not some number whose square is 4, it is the positive number whose square is 4 you might have seen, for example, the \(\pm\) in the quadratic formula
myininaya
  • myininaya
let me resay this: the square root of 4 is 2 or -2 but \[\sqrt{4}=2 \text{ and } \neq -2 \\ \text{ this is because we are suppose to read } \sqrt{ \cdot } \text{ as the princiapl square root }\]
anonymous
  • anonymous
if you have a choice, you would not need to write \[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] you could omit the \(\pm\) since apparently \(\sqrt{b^2-4ac}\) can be positive or negative
Loser66
  • Loser66
Like this sentence "what the monkey does "use both values" mean?" hahahaha............

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