mckenzieandjesus
  • mckenzieandjesus
What is the surface area of the cone? 175π cm2 224π cm2 147π cm2 273π cm2
Geometry
jamiebookeater
  • jamiebookeater
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mckenzieandjesus
  • mckenzieandjesus
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mckenzieandjesus
  • mckenzieandjesus
im using this site http://www.web-formulas.com/Math_Formulas/Geometry_Surface_of_Cone.aspx but got the wrong answer and kind of confused how to put it all in the formula..
NathalyN
  • NathalyN
A=πr(r+h2+r2)

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jdoe0001
  • jdoe0001
\(\large \textit{volume of a cone}=\cfrac{\pi r^2 h}{3}\qquad \begin{cases} r=radius\\ h=height \end{cases} \)
jdoe0001
  • jdoe0001
hmm shoot .. surface area... ok
mckenzieandjesus
  • mckenzieandjesus
13891 9/25?
mckenzieandjesus
  • mckenzieandjesus
jdoe0001
  • jdoe0001
\(\bf \textit{total surface area of a cone}=\pi r\sqrt{r^2+h^2}+\pi r^2\qquad \begin{cases} r=radius\\ h=height \end{cases} \)
mckenzieandjesus
  • mckenzieandjesus
16909.214?
mckenzieandjesus
  • mckenzieandjesus
or 703.36 those are the answers im getting..
jdoe0001
  • jdoe0001
hmm so.. which one did you get?
jdoe0001
  • jdoe0001
https://www.google.com/search?client=opera&q=pi*7*sqrt(7%5E2%2B24%5E2)%2Bpi*7%5E2&sourceid=opera&ie=utf-8&oe=utf-8&channel=suggest&gws_rd=ssl
mckenzieandjesus
  • mckenzieandjesus
so \[3.14*7\sqrt{7^{2}}+24^{2} + 3.14*7^2 =\] 16909.214
mckenzieandjesus
  • mckenzieandjesus
yeah and i got that answer u got by doing it another way.. but none of those are on my answer choices..
mckenzieandjesus
  • mckenzieandjesus
jdoe0001
  • jdoe0001
ohh hmmm your choices are in \(\huge \pi\) terms thus... you need to keep the \(\huge \pi\) without multiplying it
mckenzieandjesus
  • mckenzieandjesus
so how do i do that?
jdoe0001
  • jdoe0001
well.. just don't multiply the \(\pi\) and keep it as is, as a variable per se
mckenzieandjesus
  • mckenzieandjesus
\[7*\sqrt{7^2+24^2} + 3.14*7^2\]
mckenzieandjesus
  • mckenzieandjesus
or wait..
jdoe0001
  • jdoe0001
one sec
mckenzieandjesus
  • mckenzieandjesus
\[7*\sqrt{7^2+24^2} * 7^2 = 8575\]
mckenzieandjesus
  • mckenzieandjesus
okay.. still lost
jdoe0001
  • jdoe0001
hmmm have a typo there one sec \(\bf \textit{total surface area of a cone}=\pi r\sqrt{r^2+h^2}+\pi r^2\qquad \begin{cases} r=radius\\ h=height \end{cases} \\ \quad \\ \pi r\sqrt{r^2+h^2}+\pi r^2\implies \pi r(\sqrt{r^2+h^2}+r)\impliedby \textit{common factor} \\ \quad \\ \begin{cases} r=7\\ h=24 \end{cases}\implies \pi \cdot 7(\sqrt{7^2+24^2}+7)\implies \square ?\pi \)
mckenzieandjesus
  • mckenzieandjesus
224?
jdoe0001
  • jdoe0001
yeap
mckenzieandjesus
  • mckenzieandjesus
thank you
jdoe0001
  • jdoe0001
so in \(\pi\) terms is \(\large 224\pi\)
mckenzieandjesus
  • mckenzieandjesus
Can u finish helping me on my other question please?

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