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anonymous
 one year ago
Barry has been watching the geese that live in his neighborhood. The number of geese changes each week.
n f(n)
1 56
2 28
3 14
4 7
Which function best shows the relationship between n and f(n)?
f(n) = 28(0.5)n
f(n) = 56(0.5)n1
f(n) = 56(0.5)n
f(n) = 112(0.5)n1
anonymous
 one year ago
Barry has been watching the geese that live in his neighborhood. The number of geese changes each week. n f(n) 1 56 2 28 3 14 4 7 Which function best shows the relationship between n and f(n)? f(n) = 28(0.5)n f(n) = 56(0.5)n1 f(n) = 56(0.5)n f(n) = 112(0.5)n1

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dan815
 one year ago
Best ResponseYou've already chosen the best response.0barry needs to get a life lol

dan815
 one year ago
Best ResponseYou've already chosen the best response.0can you see how the geese keep getting halved everyday

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its only one question so the answer is b?

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.1Doesn't have to be c?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah im leaning toward c but im not sure yet

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.1I am assuming that n1 should actually be in brackets like (n1) then when f(1) then you get 0 where if you use c then it comes out as 56

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0slade prolly got the answer from someone else thats the only thing i can think

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes i should be in brackets so C is true

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no it didnt have brackets so i got confused and picked the next one that i thout

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0$$ f(1)=56\\ f(2)=28=\cfrac{f(1)}{2}\\\\ f(3)=14=\cfrac{f(2)}{2}=\cfrac{f(1)}{2^2}\\ f(4)=7=\cfrac{f(3)}{2}=\cfrac{f(1)}{2^3}\\ \cdots\\ f(n)=\cfrac{f(1)}{2^{(n1)}}=\cfrac{56}{2^{(n1)}}=56\left(\cfrac{1}{2}\right)^{n1} $$ Does this make sense?
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