## anonymous one year ago (x^–2y^–4x^3)^-2 simplify with positive exponents

1. anonymous

$(x ^{-2}y ^{-4}x^3)^{-2}$

2. dan815

okay first use this identity 1/a = a^-1

3. anonymous

$\frac{ y^8 }{ x^2 }$ This is what I got... How did you get a^-1? I may be wrong I mess up allot on equations like these. That is why I try to learn them.

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