anonymous
  • anonymous
Convert the Cartesian equation x^4 - y^4 = 16 to a polar equation? r^2 = 16/cos2θ r^4 = 16/cos2θ r^2 = 8
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
so far i have r^4(cos^4(theta)-sin^4(theta))=16
anonymous
  • anonymous
Do you know any trig identities to simplify that?
anonymous
  • anonymous
I think the answer is B, but i'm not totally sure

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anonymous
  • anonymous
I don't know I just learned this today and my worksheet doesn't say anything about it.
anonymous
  • anonymous
But I think your right.
anonymous
  • anonymous
Thank you
anonymous
  • anonymous
I think it simplifies to cos(2x)(1)
anonymous
  • anonymous
r^4cos(2x)=16 r^4=16/cos(2x)
anonymous
  • anonymous
Ok thanks!
anonymous
  • anonymous
https://www.youtube.com/watch?v=JSBUnq535vM
anonymous
  • anonymous
that explains the identity
anonymous
  • anonymous
no problem

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