Saylilbaby
  • Saylilbaby
find the excluded value pls...medal
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Saylilbaby
  • Saylilbaby
(3x^2+5x-8)/(6x+16)*(4x^2+x)/(3x^2-3x)
Saylilbaby
  • Saylilbaby
@Australopithecus @jdoe0001 @pooja195 @TheSmartOne @Awolflover1
Saylilbaby
  • Saylilbaby
2/(x^2-1)+x/(x^2-2x+1)

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Saylilbaby
  • Saylilbaby
@Astrophysics
xapproachesinfinity
  • xapproachesinfinity
let me rewrite that \(\Large \frac{(3x^2+5x-8)}{(6x+16)} \times \frac{(4x^2+x)}{(3x^2-3x)}\)
xapproachesinfinity
  • xapproachesinfinity
that's what you have?
xapproachesinfinity
  • xapproachesinfinity
for excluded values you look at what makes the denominator equal to zero
xapproachesinfinity
  • xapproachesinfinity
but before doing so we would like to simplify first factoring if possible
Saylilbaby
  • Saylilbaby
the answer was (3x^33-8)(4x+1)/6(3x+8)(x-1) @xapproachesinfinity
xapproachesinfinity
  • xapproachesinfinity
can we factor \(3x^2+5x-8\)
xapproachesinfinity
  • xapproachesinfinity
answer for what?
Saylilbaby
  • Saylilbaby
yes we can factor that @xapproachesinfinity
xapproachesinfinity
  • xapproachesinfinity
so what are the factors
Saylilbaby
  • Saylilbaby
(3x+8)(x-1) @xapproachesinfinity
xapproachesinfinity
  • xapproachesinfinity
yes!
xapproachesinfinity
  • xapproachesinfinity
so we have \(\Large \frac{(3x+8)(x-1)}{(6x+16)}\times \frac{(4x+1)}{3(x-1)}\) \(\Large \frac{(3x+8)(4x+1)}{3(6x+16)}\)
xapproachesinfinity
  • xapproachesinfinity
so what make denominator now equal to 0
xapproachesinfinity
  • xapproachesinfinity
6x+16=0 ===> x=-16/6 x=-8/3
xapproachesinfinity
  • xapproachesinfinity
excluded value -8/3
Saylilbaby
  • Saylilbaby
ok thanks can you help with the secondequation @xapproachesinfinity
xapproachesinfinity
  • xapproachesinfinity
actually i have to go for some time i fasting i need to go eat :)

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