anonymous
  • anonymous
What is the value of w in terms of x and y?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
aka "solve for \(w\) " right?
anonymous
  • anonymous
|dw:1435716265419:dw|
anonymous
  • anonymous
I'm not sure...

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More answers

anonymous
  • anonymous
if that is a straight line on the right, then \(2x+w=180\)
anonymous
  • anonymous
yea
anonymous
  • anonymous
so you can solve for \(w\) with no \(y\) in it , just \[w=180-2x\]
anonymous
  • anonymous
The answer to this is w=2x+2y-180
anonymous
  • anonymous
i have no clue how that's the answer
anonymous
  • anonymous
me neither
anonymous
  • anonymous
crap
anonymous
  • anonymous
i am sure we can figure it out if we stare long enough
anonymous
  • anonymous
yea that's the only strategy i have thus far
anonymous
  • anonymous
we got a bunch of stuff we know for example \[x+y+k=180\]
anonymous
  • anonymous
yea
anonymous
  • anonymous
\[w+2k=180\]
anonymous
  • anonymous
yea i got that
anonymous
  • anonymous
we can solve \[w+2k=180\] for \(k\) and get \[w=180-2k\]then plug that in to the first one
anonymous
  • anonymous
yea
anonymous
  • anonymous
oops that is wrong, i meant "solve for \(k\)"
anonymous
  • anonymous
\[k=\frac{180-w}{2}\]
anonymous
  • anonymous
hmmm okay
anonymous
  • anonymous
plug that in h ere \[x+y+k=180\]
Kash_TheSmartGuy
  • Kash_TheSmartGuy
This is confusing!
anonymous
  • anonymous
\[x+y+\frac{180-w}{2}=180\] then solve that for \(w\)
anonymous
  • anonymous
wow u kno what i'm just going to skip this because this is way too hard
anonymous
  • anonymous
it is not that hard takes three steps at the most
anonymous
  • anonymous
multiply by 2 get \[2x+2y+180-w=360\]
anonymous
  • anonymous
add \(w\) subtract \(360\) get \[2x+2y-180=w\]
anonymous
  • anonymous
wow you got it..... okay well lemme sit here and stare for a bit to process this..
anonymous
  • anonymous
so another method would be K=(180-x-y) w+k+k=180 w=180-2k w=180-2(180-x-y) w=180-360+2x+2y w=2x+2y-180

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