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sloppycanada
 one year ago
Ellipses
http://gyazo.com/e897fc96e592ab1e5dcba825538b6d7e
y^2/100  x^2/16 = 1
sloppycanada
 one year ago
Ellipses http://gyazo.com/e897fc96e592ab1e5dcba825538b6d7e y^2/100  x^2/16 = 1

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0center is not \((0,0)\) find the center first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it is going to look like \[\frac{(x1)^2}{a^2}\frac{(y2)^2}{b^2}=1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you need \(a\) and \(b\)

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0But wouldn't x and y be switched? Since the graph is going a different way?

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0So it's not like an ellipses that way.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435717476572:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0scuse the crappy pictures

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0No worries, mine are worse Okay so for this graph it'd be  (x^22)/100  (y^21)/16 = 1

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0Also for this one  you said it was x than y. http://gyazo.com/99da097eae7203d795aaab65586d4f48

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then i made a mistake

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0also no, not 100 and 16

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the distance from the center to the vertex is 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not the whole length from one vertex to the other, which is 10 so \(25\) goes under the \(x\) part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0similarly under the \(y\) part put a 4, not 16

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0(x^22)/25  (y^21)/4 = 1 is my final answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes want to check it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not \(x^21\) up top but rather \((x1)^2\)

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0(x2)^2/25  (y1)^2/4 = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0here is the check that \[\frac{(x2)^2}{25}\frac{(y1)^2}{4}=1\] is right http://www.wolframalpha.com/input/?i=hyperbola+%28x1%29^2%2F25%28y2%29^2%2F4%3D1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hard to tell from the graphs, but you can see from the vertices that it is correct

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0So many hyperbola questions...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there is a certain sameness to them
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