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sloppycanada

  • one year ago

This little guy is annoying. http://gyazo.com/ae8382ea043cf4d43c5dfc637f165dbf (x+11.5)^2/30.25 - (y-1.5)^2/4 = 1

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  1. jim_thompson5910
    • one year ago
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    you're trying to find the equation based on the graph?

  2. sloppycanada
    • one year ago
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    I am @jim_thompson5910

  3. jim_thompson5910
    • one year ago
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    do you see where the left edge of the box is? what x coordinate is this?

  4. sloppycanada
    • one year ago
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    -11.5

  5. jim_thompson5910
    • one year ago
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    I'm thinking -11

  6. jim_thompson5910
    • one year ago
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    since it's halfway between -12 and -10

  7. jim_thompson5910
    • one year ago
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    how about the right edge?

  8. sloppycanada
    • one year ago
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    Oh yeah... okay so -11 and 1

  9. jim_thompson5910
    • one year ago
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    add them up and divide by 2

  10. jim_thompson5910
    • one year ago
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    doing that gives you what?

  11. sloppycanada
    • one year ago
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    (x+11)^2/9 - (y-1)^2/4 = 1

  12. jim_thompson5910
    • one year ago
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    \[\Large \frac{-11+1}{2} = ??\]

  13. jim_thompson5910
    • one year ago
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    doing that calculation gives the x coordinate of the center

  14. sloppycanada
    • one year ago
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    -5

  15. jim_thompson5910
    • one year ago
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    good

  16. jim_thompson5910
    • one year ago
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    now do the same for the top and bottom edges

  17. sloppycanada
    • one year ago
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    9 - -7/2 8?

  18. jim_thompson5910
    • one year ago
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    Add not subtract \[\Large \frac{9 + (-7)}{2} = \frac{2}{2} = 1\]

  19. jim_thompson5910
    • one year ago
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    So the center is (-5,1)

  20. jim_thompson5910
    • one year ago
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    \[\Large \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\] (h,k) is the center a = half of the horizontal length of the box b = half of the vertical length of the box hyperbola looks like this |dw:1435720969381:dw|

  21. sloppycanada
    • one year ago
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    (x+5)^2/9 - (y-1)^2/4 = 1

  22. sloppycanada
    • one year ago
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    @jim_thompson5910

  23. jim_thompson5910
    • one year ago
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    I don't agree with the 9 and 4 down below

  24. jim_thompson5910
    • one year ago
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    |dw:1435721888993:dw|

  25. jim_thompson5910
    • one year ago
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    |dw:1435721928414:dw|

  26. jim_thompson5910
    • one year ago
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    |dw:1435721972999:dw|

  27. sloppycanada
    • one year ago
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    But don't I have to square the bottom?

  28. jim_thompson5910
    • one year ago
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    what do you mean?

  29. sloppycanada
    • one year ago
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    a^2 and b^2 36 and 64

  30. jim_thompson5910
    • one year ago
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    yeah a = 6 and b = 8 so a^2 = 36 and b^2 = 64

  31. sloppycanada
    • one year ago
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    Final equation- (x+5)^2/36 - (y-1)^2/64 = 1

  32. jim_thompson5910
    • one year ago
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    yes

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