A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Convert the polar equation r=4sinθ to a Cartesian equation.
Answer choices:
x^2 + y^2 = 4y
x^2 + y^2 = 4x
anonymous
 one year ago
Convert the polar equation r=4sinθ to a Cartesian equation. Answer choices: x^2 + y^2 = 4y x^2 + y^2 = 4x

This Question is Closed

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.2Hello again! We're you able to make sense of that other document that had been given? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Kind of, but I was still a little confused.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.2OK. Well let me give you a summary of key things you need to know to solve these sort of problems.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.2\[r = \sqrt{x^2+y^2}\] \[\cos(\theta) = \frac{x}{r}\] \[\sin(\theta) = \frac{y}{r}\]

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.2Those are the three most important facts you need to know. The question is... how to use them?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.2It's a good idea to convert the trig functions first. They are kind of annoying anyways. Let's start by changing the sin into something else.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.2Let's write down the change as: \[r = 4 \sin \theta\] becomes \[r = 4 \cdot (\frac{y}{r})\] Does that make sense so far?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.2Perfect! Now, if you wanted you could switch out the r's now. You would get a bit of a mess though. I'm going to be a little tricky and multiply both sides by r, to get the r's by themself.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.2\[r = 4 \cdot (\frac{y}{r})\] becomes \[r^2 = 4y\]

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.2Now this is a wonderful equation to have! Remember that r is a square root of x^2 and y^2. But since we now have r^2 the square root goes away! Like this...

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.2\[r^2 = 4y\] becomes \[(\sqrt{x^2+y^2})^2 = 4y\] which is easy \[x^2 + y^2 = 4y\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much it makes a lot more sense now! :)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.2Glad to help! Just remember, convert trig first, then see if you can make an r^2 (they are friendly), then convert r and you are done! :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.