A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

*HELP*

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @jim_thompson5910 please??

  3. rishavraj
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    wht do u think??

  4. rishavraj
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    if speed at t1 is s1 and t2 is s2 ... then rate of change of speed = (s2 - s1)/(t2 - t1)

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is that like slope kinda?

  6. rishavraj
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    value at pi = 2 and at (3 pi)/2 = -1 so rate of change \[\frac{ 2 - (-1) }{ \frac{ 3 \pi }{ 2 } - \pi }\]

  7. rishavraj
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    oooh my bad.value at pi = -1

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how would the bottom work out? just cancel the pi?

  9. UsukiDoll
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for the bottom, we need to multiply that part by \[\frac{2}{2} \] that way we can subtract that fraction because now they have the same denominators.

  10. rishavraj
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    value at (3 pi)/2 = 2 |dw:1435723454817:dw|

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so 6/pi

  12. rishavraj
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    yeah :)))

  13. UsukiDoll
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    good job! :)

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thank you! can i get a second opinion on a question?

  15. UsukiDoll
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    depends on the question, but go ahead :)

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What is the amplitude, period, and phase shift of f(x) = −3 cos(4x + π) + 6? Amplitude = 3; period = pi over two; phase shift: x = negative pi over four Amplitude = −3; period = pi over two; phase shift: x = pi over four Amplitude = −3; period = negative pi over two; phase shift: x = negative pi over four Amplitude = 3; period = 2π; phase shift: x = negative pi over four Im stuck between a and b

  17. UsukiDoll
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    uh oh. I forgot this already x.X!

  18. UsukiDoll
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @myininaya

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @rishavraj @jim_thompson5910

  20. UsukiDoll
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry ^_^ it was too long ago... and it was my weak spot during my trigonometry class too.

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its okay! thank you for helping with the other one though

  22. UsukiDoll
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you're welcome :)

  23. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    do you have anything? @rishavraj

  24. rishavraj
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    no not sure ......

  25. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    do you have anything? @rishavraj

  26. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1435724341293:dw|

  27. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1435724350479:dw|

  28. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1435724371477:dw|

  29. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1435724392822:dw|

  30. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1435724440263:dw|

  31. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so it would be a! (:

  32. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1435724524199:dw|

  33. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah looks like it

  34. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks! its that absolute values that confuse me alot

  35. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you mean the amplitude?

  36. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.