## anonymous one year ago *HELP*

1. anonymous

2. anonymous

3. rishavraj

wht do u think??

4. rishavraj

if speed at t1 is s1 and t2 is s2 ... then rate of change of speed = (s2 - s1)/(t2 - t1)

5. anonymous

is that like slope kinda?

6. rishavraj

value at pi = 2 and at (3 pi)/2 = -1 so rate of change $\frac{ 2 - (-1) }{ \frac{ 3 \pi }{ 2 } - \pi }$

7. rishavraj

oooh my bad.value at pi = -1

8. anonymous

how would the bottom work out? just cancel the pi?

9. UsukiDoll

for the bottom, we need to multiply that part by $\frac{2}{2}$ that way we can subtract that fraction because now they have the same denominators.

10. rishavraj

value at (3 pi)/2 = 2 |dw:1435723454817:dw|

11. anonymous

so 6/pi

12. rishavraj

yeah :)))

13. UsukiDoll

good job! :)

14. anonymous

Thank you! can i get a second opinion on a question?

15. UsukiDoll

depends on the question, but go ahead :)

16. anonymous

What is the amplitude, period, and phase shift of f(x) = −3 cos(4x + π) + 6? Amplitude = 3; period = pi over two; phase shift: x = negative pi over four Amplitude = −3; period = pi over two; phase shift: x = pi over four Amplitude = −3; period = negative pi over two; phase shift: x = negative pi over four Amplitude = 3; period = 2π; phase shift: x = negative pi over four Im stuck between a and b

17. UsukiDoll

uh oh. I forgot this already x.X!

18. UsukiDoll

@myininaya

19. anonymous

@rishavraj @jim_thompson5910

20. UsukiDoll

sorry ^_^ it was too long ago... and it was my weak spot during my trigonometry class too.

21. anonymous

its okay! thank you for helping with the other one though

22. UsukiDoll

you're welcome :)

23. anonymous

do you have anything? @rishavraj

24. rishavraj

no not sure ......

25. rishavraj
26. anonymous

do you have anything? @rishavraj

27. jim_thompson5910

|dw:1435724341293:dw|

28. jim_thompson5910

|dw:1435724350479:dw|

29. jim_thompson5910

|dw:1435724371477:dw|

30. jim_thompson5910

|dw:1435724392822:dw|

31. jim_thompson5910

|dw:1435724440263:dw|

32. anonymous

so it would be a! (:

33. jim_thompson5910

|dw:1435724524199:dw|

34. jim_thompson5910

yeah looks like it

35. anonymous

thanks! its that absolute values that confuse me alot

36. jim_thompson5910

you mean the amplitude?