anonymous
  • anonymous
*HELP*
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
anonymous
  • anonymous
@jim_thompson5910 please??
rishavraj
  • rishavraj
wht do u think??

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rishavraj
  • rishavraj
if speed at t1 is s1 and t2 is s2 ... then rate of change of speed = (s2 - s1)/(t2 - t1)
anonymous
  • anonymous
is that like slope kinda?
rishavraj
  • rishavraj
value at pi = 2 and at (3 pi)/2 = -1 so rate of change \[\frac{ 2 - (-1) }{ \frac{ 3 \pi }{ 2 } - \pi }\]
rishavraj
  • rishavraj
oooh my bad.value at pi = -1
anonymous
  • anonymous
how would the bottom work out? just cancel the pi?
UsukiDoll
  • UsukiDoll
for the bottom, we need to multiply that part by \[\frac{2}{2} \] that way we can subtract that fraction because now they have the same denominators.
rishavraj
  • rishavraj
value at (3 pi)/2 = 2 |dw:1435723454817:dw|
anonymous
  • anonymous
so 6/pi
rishavraj
  • rishavraj
yeah :)))
UsukiDoll
  • UsukiDoll
good job! :)
anonymous
  • anonymous
Thank you! can i get a second opinion on a question?
UsukiDoll
  • UsukiDoll
depends on the question, but go ahead :)
anonymous
  • anonymous
What is the amplitude, period, and phase shift of f(x) = −3 cos(4x + π) + 6? Amplitude = 3; period = pi over two; phase shift: x = negative pi over four Amplitude = −3; period = pi over two; phase shift: x = pi over four Amplitude = −3; period = negative pi over two; phase shift: x = negative pi over four Amplitude = 3; period = 2π; phase shift: x = negative pi over four Im stuck between a and b
UsukiDoll
  • UsukiDoll
uh oh. I forgot this already x.X!
UsukiDoll
  • UsukiDoll
@myininaya
anonymous
  • anonymous
@rishavraj @jim_thompson5910
UsukiDoll
  • UsukiDoll
sorry ^_^ it was too long ago... and it was my weak spot during my trigonometry class too.
anonymous
  • anonymous
its okay! thank you for helping with the other one though
UsukiDoll
  • UsukiDoll
you're welcome :)
anonymous
  • anonymous
do you have anything? @rishavraj
rishavraj
  • rishavraj
no not sure ......
rishavraj
  • rishavraj
@georgia545 https://mathway.com/examples/Trigonometry/Graphing-Trigonometric-Functions/Amplitude-Period-and-Phase-Shift?id=342
anonymous
  • anonymous
do you have anything? @rishavraj
jim_thompson5910
  • jim_thompson5910
|dw:1435724341293:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435724350479:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435724371477:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435724392822:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435724440263:dw|
anonymous
  • anonymous
so it would be a! (:
jim_thompson5910
  • jim_thompson5910
|dw:1435724524199:dw|
jim_thompson5910
  • jim_thompson5910
yeah looks like it
anonymous
  • anonymous
thanks! its that absolute values that confuse me alot
jim_thompson5910
  • jim_thompson5910
you mean the amplitude?

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