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- anonymous

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- chestercat

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- anonymous

i only need help doing #3
@jim_thompson5910

##### 1 Attachment

- anonymous

A(t) = 39,145[(1+ 0.03/12)1/4]^(4)(12)(-45.5)
what i have so far

- jim_thompson5910

the pic doesn't match the problem

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## More answers

- anonymous

sooo im completely wrong lol just start over then?

- jim_thompson5910

did you post the wrong pic?

- anonymous

oops i did....

##### 1 Attachment

- jim_thompson5910

you meant to say this right?
\[\Large A = P\left[ \left(1+\frac{r}{n}\right)^{\frac{1}{c}} \right]^{cnt}\]
\[\Large A = 39145\left[ \left(1+\frac{0.03}{12}\right)^{\frac{1}{4}} \right]^{4*12*t}\]

- anonymous

yes and for t i had -45.5

- jim_thompson5910

t is time in years
how is time negative?

- anonymous

idk but my teacher said that answer was right..

- anonymous

my biggest prob is solving 1.00025^1/4 because i dont have a calculator

- jim_thompson5910

he said that a negative time value is possible?

- jim_thompson5910

how strange

- jim_thompson5910

oh nvm I didn't read #2 fully lol

- jim_thompson5910

you can use this free online calculator
http://web2.0calc.com/

- jim_thompson5910

if you want to evaluate 1.00025^(1/4), make sure you type that in and hit the equal sign
don't forget the parenthesis

- anonymous

idk what im not doing right

- jim_thompson5910

I'm guessing #3 wants you to solve for r?

- jim_thompson5910

solve this for r maybe?
\[\Large 1+\frac{r}{n} = P\left[ \left(1+\frac{r}{n}\right)^{\frac{1}{c}} \right]^{cnt}\]

- jim_thompson5910

hmm not 100% sure

- anonymous

\[a(t)=39,145[(1+\frac{ .003 }{ 12 })^{(1/4)}]\] ^(4)(12)(-45.5)

- anonymous

39,145[(1.00025)^1/4]^(-2184)
-39,145=1^-2184
-39,145=1
39,145

- anonymous

where did i go wrong

- jim_thompson5910

which variable are you trying to solve for?

- jim_thompson5910

or you're just trying to evaluate 39,145[(1.00025)^1/4]^(-2184) ?

- anonymous

i guess just evaluate that cause the question asks to solve for the adjusted intrest rate

- anonymous

i feel like my equations right and i dont know why im getting it wrong ):

- jim_thompson5910

I'm stuck on the fact that they bring in c = 4, but the 'c' terms cancel (when they divide). This problem is just odd. Hmm

- anonymous

its making me mad cause i know im doing it right

- anonymous

are there any logs in here?

- jim_thompson5910

this is what I get
http://web2.0calc.com/#39145((1.00025)^(1/4))^(-2184)

- anonymous

are there any logs in here?

- anonymous

yeah thats whatt i got to

- jim_thompson5910

there's the log button at the bottom

- anonymous

@UsukiDoll

- anonymous

@UsukiDoll

- anonymous

i mean to solve this problem

- UsukiDoll

sorry I don't know how this works.

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