## anonymous one year ago &

• This Question is Open
1. anonymous

i only need help doing #3 @jim_thompson5910

2. anonymous

A(t) = 39,145[(1+ 0.03/12)1/4]^(4)(12)(-45.5) what i have so far

3. jim_thompson5910

the pic doesn't match the problem

4. anonymous

sooo im completely wrong lol just start over then?

5. jim_thompson5910

did you post the wrong pic?

6. anonymous

oops i did....

7. jim_thompson5910

you meant to say this right? $\Large A = P\left[ \left(1+\frac{r}{n}\right)^{\frac{1}{c}} \right]^{cnt}$ $\Large A = 39145\left[ \left(1+\frac{0.03}{12}\right)^{\frac{1}{4}} \right]^{4*12*t}$

8. anonymous

yes and for t i had -45.5

9. jim_thompson5910

t is time in years how is time negative?

10. anonymous

idk but my teacher said that answer was right..

11. anonymous

my biggest prob is solving 1.00025^1/4 because i dont have a calculator

12. jim_thompson5910

he said that a negative time value is possible?

13. jim_thompson5910

how strange

14. jim_thompson5910

oh nvm I didn't read #2 fully lol

15. jim_thompson5910

you can use this free online calculator http://web2.0calc.com/

16. jim_thompson5910

if you want to evaluate 1.00025^(1/4), make sure you type that in and hit the equal sign don't forget the parenthesis

17. anonymous

idk what im not doing right

18. jim_thompson5910

I'm guessing #3 wants you to solve for r?

19. jim_thompson5910

solve this for r maybe? $\Large 1+\frac{r}{n} = P\left[ \left(1+\frac{r}{n}\right)^{\frac{1}{c}} \right]^{cnt}$

20. jim_thompson5910

hmm not 100% sure

21. anonymous

$a(t)=39,145[(1+\frac{ .003 }{ 12 })^{(1/4)}]$ ^(4)(12)(-45.5)

22. anonymous

39,145[(1.00025)^1/4]^(-2184) -39,145=1^-2184 -39,145=1 39,145

23. anonymous

where did i go wrong

24. jim_thompson5910

which variable are you trying to solve for?

25. jim_thompson5910

or you're just trying to evaluate 39,145[(1.00025)^1/4]^(-2184) ?

26. anonymous

i guess just evaluate that cause the question asks to solve for the adjusted intrest rate

27. anonymous

i feel like my equations right and i dont know why im getting it wrong ):

28. jim_thompson5910

I'm stuck on the fact that they bring in c = 4, but the 'c' terms cancel (when they divide). This problem is just odd. Hmm

29. anonymous

its making me mad cause i know im doing it right

30. anonymous

are there any logs in here?

31. jim_thompson5910

this is what I get http://web2.0calc.com/#39145((1.00025)^(1/4))^(-2184)

32. anonymous

are there any logs in here?

33. anonymous

yeah thats whatt i got to

34. jim_thompson5910

there's the log button at the bottom

35. anonymous

@UsukiDoll

36. anonymous

@UsukiDoll

37. anonymous

i mean to solve this problem

38. UsukiDoll

sorry I don't know how this works.