At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

i only need help doing #3
@jim_thompson5910

A(t) = 39,145[(1+ 0.03/12)1/4]^(4)(12)(-45.5)
what i have so far

the pic doesn't match the problem

sooo im completely wrong lol just start over then?

did you post the wrong pic?

oops i did....

yes and for t i had -45.5

t is time in years
how is time negative?

idk but my teacher said that answer was right..

my biggest prob is solving 1.00025^1/4 because i dont have a calculator

he said that a negative time value is possible?

how strange

oh nvm I didn't read #2 fully lol

you can use this free online calculator
http://web2.0calc.com/

idk what im not doing right

I'm guessing #3 wants you to solve for r?

hmm not 100% sure

\[a(t)=39,145[(1+\frac{ .003 }{ 12 })^{(1/4)}]\] ^(4)(12)(-45.5)

39,145[(1.00025)^1/4]^(-2184)
-39,145=1^-2184
-39,145=1
39,145

where did i go wrong

which variable are you trying to solve for?

or you're just trying to evaluate 39,145[(1.00025)^1/4]^(-2184) ?

i guess just evaluate that cause the question asks to solve for the adjusted intrest rate

i feel like my equations right and i dont know why im getting it wrong ):

its making me mad cause i know im doing it right

are there any logs in here?

this is what I get
http://web2.0calc.com/#39145((1.00025)^(1/4))^(-2184)

are there any logs in here?

yeah thats whatt i got to

there's the log button at the bottom

i mean to solve this problem

sorry I don't know how this works.