anonymous
  • anonymous
Write an equation of hte line, in point-slope form, that passes through the two given points. points(-15, 7)(5,-3) (posting picture of answers)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
I picked answer C
Jack1
  • Jack1
m = y2-y1/x2-x1 = -10/20 = - 1/2 so yeah, that's the only one with an M value of -1/2

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Jack1
  • Jack1
id go C too ;)
anonymous
  • anonymous
Yay! I get so happy when I get math questions right. :P I'm bad at math. I have 2 more(including this one) i'm not sure of
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anonymous
  • anonymous
this is the last one
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Sepeario
  • Sepeario
like @Jack1 did, or you could firstly work out the gradient, and substitute the values into a point gradient formula.
Jack1
  • Jack1
a) \(\large y = -16x^2 +15 +110x\) do you know how to find the derivative of this? (y')
anonymous
  • anonymous
no..
Jack1
  • Jack1
hmmm... k k well idk how else to do it, sorry so: \(\Large y = -16x^2 +15 +110x\) \(\Large y = -16x^{\color{red}{2}} +110x^{\color{blue}{1}} +15x^\color{green}{0}\) \(\Large y' = \color{red}{2} \times-16x^{\color{red}{2}-1} + \color{blue}{1} \times 110x^{\color{blue}{1}-1} +\color{green}{0} \times 15x^{\color{green}{0}-1} \) \(\Large y' = \color{red}{-32x^1} + \color{blue}{110x^0} + \color{green}{0}\) \(\Large y' = \color{red}{-32x^1} + \color{blue}{110} \) this is the gradient
Jack1
  • Jack1
|dw:1435739203953:dw|
Jack1
  • Jack1
\(\large y′=−32x+110\) gradient = 0 at the turning point (highest point) \(\large 0=−32x+110\) \(\large -110=−32x\) \(\large -110/-32=x\) so the time it takes to get to the highest point = 110/32 = 3.44 seconds (ish)
Jack1
  • Jack1
does this make sense? @kimberlyalice
anonymous
  • anonymous
Yes it does
anonymous
  • anonymous
Sorry, I had to go eat breakfast cause I'm fasting so it's really early in the morning.
Jack1
  • Jack1
nah, chill, all good, i'm makin snacks now too, freakin starving sweet, so if it reaches the peak ht at 3.44 seconds... how long from when its fired to when it hits the ground?
anonymous
  • anonymous
Would the peak height be about half the entire path of the object?
anonymous
  • anonymous
About 7 seconds
Jack1
  • Jack1
yeps, perfect so only 1 answer has 7 seconds
anonymous
  • anonymous
That means I was right!! This is so exciting!
anonymous
  • anonymous
THANK YOU!
Jack1
  • Jack1
well... 1 sensible answer B is kinda low, sáll 3.4 feet isnt very high
Jack1
  • Jack1
weait i didnt finish omg im so sorry :(
anonymous
  • anonymous
It's okay. I jumped too quickly :)
anonymous
  • anonymous
Is it A? The height is higher
Jack1
  • Jack1
yep, a to prove: just plug x =3.44 into first equation y=−16x2+15+110x y = height = 204.06
anonymous
  • anonymous
Ahh, I see! Thank you!
anonymous
  • anonymous
Can you help me with the last one?
Jack1
  • Jack1
b) ??? maybe, will try.... so the difference each time is -3 7... -3 = 4... -3 = 1... -3 = -2... etc... but it's supposed to be recursive... so doesnt that mean it eventually comes back to 7?
anonymous
  • anonymous
I believe so..
UsukiDoll
  • UsukiDoll
Recursion is the process of choosing a starting term and repeatedly applying the same process to each term to arrive at the following term. Recursion requires that you know the value of the term immediately before the term you are trying to find.
Jack1
  • Jack1
i'm out then, sorry :(
anonymous
  • anonymous
can you help me @UsukiDoll
anonymous
  • anonymous
it's okay @Jack1
Jack1
  • Jack1
how do i medal u @UsukiDoll ? sorry ive given mine away for this q already
UsukiDoll
  • UsukiDoll
er.. who has medal who though?
UsukiDoll
  • UsukiDoll
and a user can't medal 2 people at the same time :/
anonymous
  • anonymous
I can start a new question and you can give a medal @Jack1
UsukiDoll
  • UsukiDoll
k that sounds good.
Jack1
  • Jack1
do it!

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