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anonymous
 one year ago
1 Question Algebra 2
anonymous
 one year ago
1 Question Algebra 2

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UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2Recursion is the process of choosing a starting term and repeatedly applying the same process to each term to arrive at the following term. Recursion requires that you know the value of the term immediately before the term you are trying to find.

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0yay, cheers @KimberlyAlice and @UsukiDoll ;P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so how would I find the equation for this problem? Thanks @Jack1 :P

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so examples of recursion formulas are \[a_1 = 4, a_n = 2a_{n1}\] or \[a_1=4 , a_{n+1} = 2a_n\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so what is the \[a_1 \] in this problem?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2we need to know what a_1 is or we are stuck

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a1 would be the recursive number?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2well we need to figure out the next term it's like a chain.. but we need it to start at \[a_n \] where n = 1

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2what's the starting number? that's a_n when n =1

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ok.. so \[\large a_1=7\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That limits the choices to B and D

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so now we need to figure out ... we need to get to 4 somehow but what recursion formula will allow us to do that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No wait...we would get 3

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2yeah that's what I mean.. we need to get to 4's land

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2we know the difference in each number is 3

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2alright our starting point is \[a_1 = 7 \] so now we need a formula to get to 4

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2OH how I wish I can do this \[a_n=a_{n1}3 \] where n = 2 \[a_2=a_{21}3 \] \[a_2=a_{1}3 \] since \[a_1 = 7\] \[a_2=73 \] \[a_2=4 \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ok I think the multiple choices are flawed. Just look what I've done.. I got a_2 to appear as 4

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2hey! There's a typo in your choices. You want the last choice with a  sign instead

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2And I'll prove it so now we have \[a_1 = 7, a_2 =4\] so now our next recursive formula \[a_n=a_{n1}3 \] let n = 3 \[a_3=a_{31}3\] \[a_3=a_{2}3\] since \[a_2=4 \] \[a_3=43\] \[a_3=1\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2see the pattern ... Now I have 7 4 1

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so I have to do this 3 more times... for 2 5 and ?!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm confused...which answer choice is this?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2or maybe not.. \[a_4 = 2, a_5 = 5\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2there's a typo in the choice we need

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2but.. .we can use the formula I have to get our next number.. we know that a_1 = 7 we need a_6

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[{a_6}=a_{61}3\] \[{a_6}=a_{5}3\] since \[a_5= 5\] \[{a_6}=53\] \[{a_6}=8\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2It's the last choice with that typo that shouldn't be there.!!!!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2because should that stand... a_1 would've been 10 if it was subtraction it would've been 4

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0why not \(\Large a_n = 10 3(n)\)?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0@UsukiDoll doesnt that fit?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2look at the choices we are given

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2it's the last choice with the typo. trust me! We got the beginning which is a_1 is 7 we needed to find a_6 which is 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for all your help @Jack1 and @UsukiDoll

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0np but psh, was all @UsukiDoll , i did nothing

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2"because should that stand... a_1 would've been 10 if it was subtraction it would've been 4 " oy I meant a_2 would've been 10 if we had a + a_1 = 7 a_2 =4 a_3 =1 a_4 =2 a_5 = 5 a_6 = 8 but the formula is \[\large a_n=a_{n1}3 \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand. thank you!
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