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sloppycanada
 one year ago
Following graph is equal to what equation?
I believe for this one it is equal to 
http://gyazo.com/475495bdd392f70271f92a9bbc31f562
sloppycanada
 one year ago
Following graph is equal to what equation? I believe for this one it is equal to  http://gyazo.com/475495bdd392f70271f92a9bbc31f562

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sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435756207246:dw

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0@UsukiDoll Help me, this is just checking what I've done for these evil review problems.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1oh this is a graph transformation.. so we compare f(x) = 2^x and create some sort of transformation to have the blue line

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0Yup! I have five of them on this torturous review packet

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1what do you notice? we have the original equation but there's something going on for the blue line

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1is there a rotation or a reflection?

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0I think it's a reflection.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yes we are reflecting.. Are we reflecting along the y axis or the x axis?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1for reflection y=f(x) reflection along the y axis y= f(x) reflection along the x axis

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1woohoo! but we're still not done.. we may have reflect but is the reflected graph going down, up, left, or right ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1probably not because if you're shifting to the right.. we won't have an intersection point which is (0,1)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435757215889:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so what direction do I need to go so my new graph and the old graph intersect at (0,1)?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1oy yah dw:1435757310996:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yeah . by how many units?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so now we have g(x) = 2^x + ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1ok.. but the intersection point will be (0,2) instead.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1mhm! so now our g(x) = 2^x+2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1it's 3:33 in the morning.. so I'm going to take a break from answering questions and log off to go bed...

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0I think that's it for the problem right? Thanks a bunch you've been really helpful.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yup that's it... you can check this graph for reference.
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