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anonymous
 one year ago
the question is in the picture,
why when i go from (1) or (a) i get different equation for the same g' ?
https://dl.pushbulletusercontent.com/X0Sg1DgSq9wucZsrYb1KCdHUr2VWY2rJ/IMG_20150701_161911.jpg
anonymous
 one year ago
the question is in the picture, why when i go from (1) or (a) i get different equation for the same g' ? https://dl.pushbulletusercontent.com/X0Sg1DgSq9wucZsrYb1KCdHUr2VWY2rJ/IMG_20150701_161911.jpg

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This seems to be using usubstitution try this: https://www.khanacademy.org/math/integralcalculus/integrationtechniques/u_substitution/v/usubstitution

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0From a to b, did you divide by [g(x)]^4 ?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1did you try it with an actual example?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[g(x)=\sin(x), f(x)=\frac{1}{\sin^3(x)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0way to try with numbers? f(x) and g(x) can be any equations

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[f'(x)=\frac{3\cos(x)}{\sin^4(x)}\] and so

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[g'(x)=\frac{1}{3}f'(x)g^4(x)\] or \[\cos(x)=\cos(x)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but i want to do implicit derivering, and stay with f(x) and g(x). are (3) and (c) the same?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0solve C for g' and check

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK, got it, thanks! in (c): \[fg^3 \] = 1
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