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anonymous

  • one year ago

What values of x make the two expressions below equal? (2x+1)(x-7)/11(x-7)= 2x+1/11 A. All real numbers B. All real numbers except -1/2 C. All real numbers except 7 D. All real numbers except -1/2 and 7

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  1. DanJS
    • one year ago
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    missing parenthesis

  2. DanJS
    • one year ago
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    maybe

  3. anonymous
    • one year ago
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    The best way to go about this problem is for you to plug in the numbers where stated "except"" to see if they work.

  4. DanJS
    • one year ago
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    \[\frac{ (2x+1)(x-7) }{ 11(x-7) }=\frac{ 2x+1 }{ 11 }\] is that it

  5. anonymous
    • one year ago
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    yes that's what I wrote

  6. anonymous
    • one year ago
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    If not A, but if they do you'd be picking one of the B to D. Simple right?

  7. DanJS
    • one year ago
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    group the entire numerator in a bra kets

  8. DanJS
    • one year ago
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    simplify, (x-7) can cancel in the first, but you must keep in mind that x cant be 7, it will make the original expression undefined

  9. DanJS
    • one year ago
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    then both are over 11, and you can multiply both sides by 11 to cancel those... left with 2x+1 = 2x+1 , true, all reals

  10. anonymous
    • one year ago
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    so if you cancel x-7 out, top and bottom you're left with (2x+1)-11 right?

  11. anonymous
    • one year ago
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    /11

  12. DanJS
    • one year ago
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    yes, \[\frac{ 2x+1 }{ 11 }= \frac{ 2x+1 }{ 11 }\]

  13. DanJS
    • one year ago
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    It is like saying, 1 = 1, True statement, any value for x is possible there

  14. DanJS
    • one year ago
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    remember you canceled out (x-7) in the denominator though, so x-7 can not be zero

  15. anonymous
    • one year ago
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    same exact thing on both sides except the left one has parentheses

  16. DanJS
    • one year ago
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    right, if you have the same things on both sides, then the variable can be any real number. Except here it can not be 7 since you cancelled out x-7 in the denominator, you cant have x-7=0 or x=7

  17. DanJS
    • one year ago
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    zero in the bottom is bad

  18. anonymous
    • one year ago
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    so it would be all real numbers except 7?

  19. DanJS
    • one year ago
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    yes

  20. anonymous
    • one year ago
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    thank you ;)-

  21. anonymous
    • one year ago
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    :)

  22. DanJS
    • one year ago
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    i forget what they call those solutions x=7, some term

  23. anonymous
    • one year ago
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    did not know that myself haha

  24. DanJS
    • one year ago
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    you can check, put x=7 and see if both sides are the same...

  25. anonymous
    • one year ago
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    i did

  26. DanJS
    • one year ago
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    extraneous solutions, just popped into my head, check that definition out if it sounds familiar.

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