anonymous
  • anonymous
What is the average rate of change of temperature with respect to time over the evening hours from 6 PM to 10 PM? Interpret this value in a complete sentence.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
Time of Day 10 AM 12 Noon 2 PM 4 PM 6 PM 8 PM 10 PM Temperature (4072-03-01-01-00_files/i0290000.jpg) 30 35 36 36 34 30 28
anonymous
  • anonymous
a. 4072-03-01-01-00_files/i0290001.jpg degrees per hour; The temperature drops at an average rate of 6 degrees per hour from 6 PM to 10 PM. b. 4072-03-01-01-00_files/i0290002.jpg degrees per hour; The temperature drops at an average rate of 6 degrees per hour from 6 PM to 10 PM. c. 4072-03-01-01-00_files/i0290003.jpg degrees per hour; The temperature drops at an average rate of 1.5 degrees per hour from 6 PM to 10 PM. d. 4072-03-01-01-00_files/i0290004.jpg degrees per hour; The temperature drops at an average rate of 1.5 degrees per hour from 6 PM to 10 PM.
Vocaloid
  • Vocaloid
The images won't load on my computer but... the average rate of change in a function f(x) from A to B can be represented by [f(B)-f(A)]/(B-A) in this case, we would use 6 PM and 10 PM as A and B, and calculate the average rate of change by using (temperature at 10PM - temperature at 6 PM)/(10-6)

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Vocaloid
  • Vocaloid
if I'm reading the table correctly, it looks like the temperature at 10PM is 28 and the temperature at 6 PM is 34?
anonymous
  • anonymous
yes sorry about the images i didnt know how to add a table to here
anonymous
  • anonymous
thank you soooooooooo much lol your real mvp the answer is -6
anonymous
  • anonymous
dang nvm it was -1.5 lmao i must of put it in the calculator wrong
Vocaloid
  • Vocaloid
(28-34)/(10-6) = -6/4 = -1.5 I think you forgot the denominator
anonymous
  • anonymous
ohhhhh okay thankyou :)

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