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- anonymous

What is the average rate of change of temperature with respect to time over the evening hours from 6 PM to 10 PM? Interpret this value in a complete sentence.

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- anonymous

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- anonymous

Time of Day
10 AM
12 Noon
2 PM
4 PM
6 PM
8 PM
10 PM
Temperature (4072-03-01-01-00_files/i0290000.jpg)
30
35
36
36
34
30
28

- anonymous

a.
4072-03-01-01-00_files/i0290001.jpg degrees per hour; The temperature drops at an average rate of 6 degrees per hour from 6 PM to 10 PM.
b.
4072-03-01-01-00_files/i0290002.jpg degrees per hour; The temperature drops at an average rate of 6 degrees per hour from 6 PM to 10 PM.
c.
4072-03-01-01-00_files/i0290003.jpg degrees per hour; The temperature drops at an average rate of 1.5 degrees per hour from 6 PM to 10 PM.
d.
4072-03-01-01-00_files/i0290004.jpg degrees per hour; The temperature drops at an average rate of 1.5 degrees per hour from 6 PM to 10 PM.

- Vocaloid

The images won't load on my computer but...
the average rate of change in a function f(x) from A to B can be represented by
[f(B)-f(A)]/(B-A)
in this case, we would use 6 PM and 10 PM as A and B, and calculate the average rate of change by using
(temperature at 10PM - temperature at 6 PM)/(10-6)

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- Vocaloid

if I'm reading the table correctly, it looks like the temperature at 10PM is 28 and the temperature at 6 PM is 34?

- anonymous

yes sorry about the images i didnt know how to add a table to here

- anonymous

thank you soooooooooo much lol your real mvp the answer is -6

- anonymous

dang nvm it was -1.5 lmao i must of put it in the calculator wrong

- Vocaloid

(28-34)/(10-6) = -6/4 = -1.5
I think you forgot the denominator

- anonymous

ohhhhh okay thankyou :)

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