anonymous
  • anonymous
Help please?
Mathematics
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anonymous
  • anonymous
Help please?
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
3 turning points, should be interesting!
anonymous
  • anonymous
I have no idea how to start it. Should I derive it first and then find the values?
anonymous
  • anonymous
I got 0 and -3

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anonymous
  • anonymous
@mukushla was right, f'(x)=0 at the turning point
anonymous
  • anonymous
DanJS
  • DanJS
can you find \[\frac{ d }{ dx }f(x)\]
DanJS
  • DanJS
that expression will give you the slope of any tangent line to the curve at a point
anonymous
  • anonymous
When I derive it I got 6x^2+12x
DanJS
  • DanJS
You just have to remember, \[\frac{ d }{ dx }[x^n]= n*x ^{n-1}\]
DanJS
  • DanJS
right, now set that slope expression to what they want, zero
DanJS
  • DanJS
horizontal line, zero slope
anonymous
  • anonymous
Dan the man!
DanJS
  • DanJS
(6x)(x+2) = 0 x can be 2 values , each quantity zero
anonymous
  • anonymous
Factors right?
DanJS
  • DanJS
6x=0 or x+2=0 horizontal tangent line
DanJS
  • DanJS
use those x values in the original f(x) and find out each corresponding y value (x,y)
DanJS
  • DanJS
or nvermind, they dont want it
anonymous
  • anonymous
You get all 3 values Dan?
DanJS
  • DanJS
it is a cubic function , it turns around 2 times,
anonymous
  • anonymous
So it would be -2 and 0?
DanJS
  • DanJS
http://awesomescreenshot.com/0b9514fn7e
DanJS
  • DanJS
right
DanJS
  • DanJS
Take first derivative, set that expression to zero, solve for the values of x for each tangent line if they exist
anonymous
  • anonymous
Alright thank you so much!
DanJS
  • DanJS
np
anonymous
  • anonymous
as usual, well done @DanJS

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