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nuccioreggie

  • one year ago

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  1. nuccioreggie
    • one year ago
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    Meg rolled a fair six-sided die 28 times. The table below shows the number of times each number was rolled: Number Cube Experiment Number on the Cube Number of Times Appeared 1 2 2 7 3 9 4 4 5 6 6 0 According to the results in the chart, what is the experimental probability of getting a number less than 3 on the die? 19 over 28 9 over 28 7 over 28 2 over 28

  2. DanJS
    • one year ago
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    experimental probability, what happened actually ?

  3. DanJS
    • one year ago
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    empirical

  4. DanJS
    • one year ago
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    (number of times event happened) / (total events)

  5. nuccioreggie
    • one year ago
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    You want me to show you a picture of the question or you get it already?

  6. DanJS
    • one year ago
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    how many times did he roll a number less than 3, a 2 or a 1 ?

  7. nuccioreggie
    • one year ago
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    Ummm hold on

  8. DanJS
    • one year ago
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    (number of times rolling a 2 or a 1) / ( total # of rolls)

  9. nuccioreggie
    • one year ago
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    So what do i do can you explain please

  10. DanJS
    • one year ago
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    add up the total times he actually rolled less than 3, and divide that by his total number of rolls

  11. DanJS
    • one year ago
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    (7 + 2) / 28

  12. DanJS
    • one year ago
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    That is the experimental/empirical/"real world" probability

  13. nuccioreggie
    • one year ago
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    I got 0.3214285714

  14. DanJS
    • one year ago
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    just simplify the fraction, 9 out of 28 rolls he hit a 1 or 2

  15. DanJS
    • one year ago
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    \[\frac{ total ~ 1 ~or~2}{ total~rolls }=\frac{ 2+7 }{ 2+7+9+4+6+0 } = \frac{ 9 }{ 28 }\]

  16. nuccioreggie
    • one year ago
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    So the answer is B

  17. nuccioreggie
    • one year ago
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    So the answer is B

  18. DanJS
    • one year ago
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    sorry, yes b

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