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anonymous
 one year ago
What is the vertex of this quadratic function?
f(x) = 2x2 + 4x − 5
anonymous
 one year ago
What is the vertex of this quadratic function? f(x) = 2x2 + 4x − 5

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DanJS
 one year ago
Best ResponseYou've already chosen the best response.0which math class are you taking

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0so you need to turn y = ax^2 + bx + c into y = a*(xh)^2 + k the vertex form

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0the vertex in that is the point (h,k)

Jenma
 one year ago
Best ResponseYou've already chosen the best response.0U know how to find the axis of symmetry?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0you can play with that , or simply remember, the x coordinate of the vertex of y = ax^2 + bx + c is x = b / (2*a)

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0as jenma said , or also the axis of symm

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0then use that x value , and calculate what y is,, the point (x,y) is the vertex

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0here is an example i just found... http://hotmath.com/hotmath_help/topics/vertexofaparabola.html

Jenma
 one year ago
Best ResponseYou've already chosen the best response.0Yes @DanJS . Find the axis of symmetry first and then when u find the answer u would do the substitute of the equation and u will find the vertex...
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