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anonymous

  • one year ago

What is the vertex of this quadratic function? f(x) = 2x2 + 4x − 5

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  1. DanJS
    • one year ago
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    which math class are you taking

  2. anonymous
    • one year ago
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    math2

  3. DanJS
    • one year ago
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    algebra

  4. anonymous
    • one year ago
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    oh yeah

  5. DanJS
    • one year ago
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    so you need to turn y = ax^2 + bx + c into y = a*(x-h)^2 + k the vertex form

  6. DanJS
    • one year ago
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    the vertex in that is the point (h,k)

  7. anonymous
    • one year ago
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    i dont get it

  8. Jenma
    • one year ago
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    U know how to find the axis of symmetry?

  9. DanJS
    • one year ago
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    you can play with that , or simply remember, the x coordinate of the vertex of y = ax^2 + bx + c is x = -b / (2*a)

  10. DanJS
    • one year ago
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    as jenma said , or also the axis of symm

  11. DanJS
    • one year ago
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    then use that x value , and calculate what y is,, the point (x,y) is the vertex

  12. DanJS
    • one year ago
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    here is an example i just found... http://hotmath.com/hotmath_help/topics/vertex-of-a-parabola.html

  13. DanJS
    • one year ago
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    gl

  14. anonymous
    • one year ago
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    ty

  15. Jenma
    • one year ago
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    Yes @DanJS . Find the axis of symmetry first and then when u find the answer u would do the substitute of the equation and u will find the vertex...

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