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anonymous

  • one year ago

Algebra Question

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  1. sloppycanada
    • one year ago
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    ?

  2. anonymous
    • one year ago
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    If \[\frac{ 3 }{ 4 } = \frac{ 6}{ x } = \frac{ 9 }{ y } \] , then x +y = ?

  3. SolomonZelman
    • one year ago
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    you can solve for x, and solve for y, by making the following conclusions out of your initial statement (what you wrote above). (Hope you know why they are valid) \(\large\color{black}{ \displaystyle \frac{3}{4}=\frac{6}{x} }\) and \(\large\color{black}{ \displaystyle \frac{3}{4}=\frac{9}{y} }\)

  4. anonymous
    • one year ago
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    oh so this also follows the transitive property of equality

  5. SolomonZelman
    • one year ago
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    yes, if you have `a=b=c` then you can conclude that: `a=b` `a=c` or `b=c`

  6. SolomonZelman
    • one year ago
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    this way we can solve for x and solve for y. (Have you found any of the unknown variables) ?

  7. anonymous
    • one year ago
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    Yes I have :D After cross multiplying: 3x= 24 and 3y = 26 and then dividing both equations by 3 on both sides gave me x = 8 and y = 12 and therefore x + y = 12 + 8 = 20 Did I do this right or was there a mistake somewhere?

  8. SolomonZelman
    • one year ago
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    you mea 3y=27?

  9. SolomonZelman
    • one year ago
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    x=8 is correct, check your y.

  10. SolomonZelman
    • one year ago
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    yes

  11. anonymous
    • one year ago
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    hmm

  12. SolomonZelman
    • one year ago
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    3y=36 yu meant 36 not 26

  13. SolomonZelman
    • one year ago
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    so, y=12, x=8 x+y=8+12=20 RIGHT !!

  14. anonymous
    • one year ago
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    OH haha

  15. anonymous
    • one year ago
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    I was like hmm where did you get 27 from haha, thanks :)

  16. SolomonZelman
    • one year ago
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    Yes, I got confused by 26 there (I thought you meant 27, but the keyboard was off by the first digit.... In any case, you are always welcome:)

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