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anonymous
 one year ago
What is the value of Fraction 1 over 2x3 + 3.4y when x = 3 and y = 4?
anonymous
 one year ago
What is the value of Fraction 1 over 2x3 + 3.4y when x = 3 and y = 4?

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2hint: \[\Large \frac{1}{{2{x^3} + 3.4y}} \to \frac{1}{{2 \times \left( {{2^3}} \right) + \left( {3.4 \times 4} \right)}} = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2hint: \[\frac{1}{{2 \times \left( {{2^3}} \right) + \left( {3.4 \times 4} \right)}} = \frac{1}{{16 + 13.6}} = \frac{1}{{29.6}} = ...?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino im really bad at fractions but i think its 31.6?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2it is: \[\Large \frac{1}{{2 \times \left( {{2^3}} \right) + \left( {3.4 \times 4} \right)}} = \frac{1}{{16 + 13.6}} = \frac{1}{{29.6}} = 0.0338\] approximated value

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2\[\large \frac{1}{{2 \times \left( {{2^3}} \right) + \left( {3.4 \times 4} \right)}} = \frac{1}{{16 + 13.6}} = \frac{1}{{29.6}} = 0.0338\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0these are the choices though 15.85 18.1 27.1 31.6

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2Sorry I have made an error since we have to substitute x=3 before Nevertheless, my expression above is wrong.

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2please write your expression using the editor, or make a drawing of your expression

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435768036043:dwwhen x=3 and y=4

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok! then we have: \[\frac{1}{2}{x^3} + 3.4y \to \frac{1}{2} \times {3^3} + 3.4 \times 4 = \frac{{27}}{2} + 13.6 = ...?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay thank you (: @Michele_Laino
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