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anonymous
 one year ago
Math help!
anonymous
 one year ago
Math help!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0should be where dy/dx is undefined. Do you have a derivative?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When you take the derivative of y² you have to use the chain rule/implicit differentiation, so multiply by dy/dx. Now solve for dy/dx 3x²  2y(dy/dx) + 2x = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So would it just be 2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no. where did you get 2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or how I should say?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I thought you would just derive 2y to get 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok. You actually have to solve the equation derivative for dy/dx by moving everything else to the other side. \[3x^22y \frac{ dy }{ dx }+2x=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I would get 2y by itself by moving 3x^2 and 2x to the other side?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I would get 2ydy/dx=3x^22x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right. Now divide by 2y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it would be 3x^2/2y+x/y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes :) BUT it's easier to keep it as one fraction because you need to find the undefined locations and it's just easier with one fraction instead of multiples, especially on more complex problems. \[\frac{ dy }{ dx }=\frac{ 3x^2+2x }{ 2y }\] since we're looking for vertical tangent lines we need where dy/dx is undefined. That would be where the denominator is 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would I have to do the quotient rule for this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no. just 2y = 0 to get the yvalue

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Y would equal 0 then

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes. then plug that into the original equation to find the xcoordinates

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the point would be (0,0)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's one of them. There's another x³ + x² = 0 x²(x + 1) = 0
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