anonymous
  • anonymous
In this triangle, the product of sin B and tan C is , and the product of sin C and tan B is . NextReset
Geometry
katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
got formula right?
anonymous
  • anonymous
no

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anonymous
  • anonymous
sin B = b/a
anonymous
  • anonymous
tan (B) = b/c
anonymous
  • anonymous
is it correct?
anonymous
  • anonymous
i have to see
anonymous
  • anonymous
i think got formula
anonymous
  • anonymous
for first question the product of sin B and tan C : hence sin B x tan C =b/a x c/b
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anonymous
  • anonymous
u can refer the graph that i draw..
anonymous
  • anonymous
this is the formula : SOH... Sine: sin(θ) = Opposite / Hypotenuse ...CAH... Cosine: cos(θ) = Adjacent / Hypotenuse ...TOA Tangent: tan(θ) = Opposite / Adjacent

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