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What do you think ?
im not sure:/
This will help :-) Let me know if you have any questions. https://www.desmos.com/calculator/nbdcxgdjta
I plotted it for you.
ok do i copy it on my graph then
Yes, you can do that.
What I gave you is what the graph is going to look like. The area that over laps are the solutions.
so (1.5,0) and (0,-3)
1.8 and 0.6
What are those points for??
its from the graph u gave me
do i need points for this equation?
To graph it yes on paper yes. TO do that you need to turn the equilities into equations and then plot the lines For instance 3x+y≤ 6 = 3x+y=6 4x-2y>6 = 4x-2y= 6 Now we plot these equation of a line 3x+y=6 4x-2y= 6 Lets do the first equation of the line 3x+y=6 When x = 1 3x+y=6 3(1)+y=6 3(1)+y=6 3+y=6 y=6-3 y=3 So we have are first point for that line/equation which is (1,3) but we need one or two more to draw our line. Use the number 2 instead of one but do it the same way I did for number 1. Do you understand?
You can also use your mouse on that site I gave you and click on the line and hold down to drag and you can see the points
and the 4x-2y= 6 would be 0,3 right @Nixy