At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
first factor out of x, can you do that for me?
x ( 4x^2 + 43x + 30 ) ?
now, lets focus on just the 4x²+43x+30
you know that if you choose (2x )(2x ) that is not going to give an odd coefficient 43 in a middle term, therefore you have to choose (4x )(x )
and you know that you have (4x + 1)(x + ) (2 pluses, because your trinomial is positive entirely)
now you have to choose two constant factors of 30 to fill it in.
The factors are 1, 2, 3, 5, 6, 10, 15, 30
yes, possible picks 1 & 30 2 & 15 3 & 10 5 & 6
4x²+43x+30 (4x + )(x + )
The rule it that a+b=43 and ab=30?
im not entirely sure
30×1=30, but 30 & 1 don't make the a+b=43
`(4)a+(1)b=43` and `ab=30`
the 10 +3
you multiply on of the numbers by 4 and the other by 1 (multiplying by coefficients of x, just as you would if you were to expand it)
bc 4(10) + 3 = 43
4x²+43x+30 (4x + )(x + ) fill it for me please...
(4x + 10)(x + 3) ?
wait, this would give a middle term of (10 • x) + (4x • 3) = 10x+12x=22x
the other way around
so (4x + 3)(x + 10) ?
4x³ + 43x² + 30x x ( 4x² + 43x + 30 ) x (4x + 3)(x + 10)
` x (4x + 3)(x + 10) ` is it.... you can't factor it more. DONE
thx so much