you can take a square to demonstrate this.
that is when all dimensions are doubled.
you can see that when you doubled the dimensions your square got 4 times bigger, right?
(same is true when doubling dimensions in a parallelogram)
i really suck at this stuff
ok, so if you double the dimensions of a parallelogram your area will be 4 times bigger|dw:1435779175933:dw|
so if your area of a parallelogram is 14, then when dimensions are doubled the area is going to be?
(or, are you done with question 1 already?)
is it 28
14 • 4 = ?
your area is FOUR times bigger when dimensions are doubled.
Now, your next q. I will put it up again not to scroll up....
` ` For a game, Tony has a rectangle drawn on a piece of paper that has an area of 18 in.2. What should he do to the dimensions in order to have a similar rectangle that's area is only 2 in.2? Divide them by nine. Divide them by six. Divide them by three. Multiply them by three. ` `
you mean area of 18 in², and you want to multiply/divide the dimensions by some number, so that the area is only 2 in².
so your rectangle has an area of `L•W` In this case, we know that: L • W = 18 but we want that to be 2
is it C
when you multiply the dimensions times this number (call it x), you are multiplying each dimensions by x, so our new equation is going to be (L•x) • (W • x)=2 and we know (L) • (W)=2
(L•x) • (W • x)=2 (L•W) • (x • x)=2 (L•W) • (x²)=2 substitue u=L•W u • x²=2 x²=2/u again, we know that L•W=18 (or u=18) x²=2/u x²=2/18 x²=1/9 x=1/3 (we don't consider negative scale factors)
So, you would need to multiply times 1/3. And multiplying times 1/3 is same as dividing by 3. Yes, C is correct.
yw (if you want to know how I put up • × ÷ ≈ and all that just let me know. it would work on most sites and word doc)