anonymous
  • anonymous
Rickey has 7 over 8 cup of cereal in a bowl. He then gave two 1 over 4 cups of cereal from his bowl to his little sister. Which of the following best explains the amount of cereal left in Rickey's bowl?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
5/8
anonymous
  • anonymous
4x2=8 so 7/8 -2= 5/8
anonymous
  • anonymous
So Rickey has \(\large \frac{7}{8}\) and he gives away 2 \(\large \frac{1}{4}\) bowls. This can be shown with the equation \[\large \frac{7}{8}~-~(2 \times \frac{1}{4})=~?\] Can you solve that?

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More answers

anonymous
  • anonymous
-2/8 not - 2 sorry
mathstudent55
  • mathstudent55
@LegendarySadist You meant: \(\large \dfrac{7}{8}~-~(\dfrac{2}{2} \times \dfrac{1}{4})=\) which then becomes \(\large =\dfrac{7}{8}~-~\dfrac{2}{8} \) \(\large =\dfrac{5}{8} \)
anonymous
  • anonymous
It says "2 1 over 4 cups". Would that not be \(\large 2 \times \frac{1}{4}\)?
anonymous
  • anonymous
Since he's giving away 2 \(\large \frac{1}{4} \normalsize th\) cups, that's the same as giving away 1/2 cup. So \[\large \frac{7}{8}~-~\frac{4}{8}~=~\frac{3}{8}\]
mathstudent55
  • mathstudent55
Sorry. You are absolutely correct. I didn't notice the two spelled out. I only looked at the numbers.
mathstudent55
  • mathstudent55
@WinterBlade1222 Ignore my answer above. Follow @LegendarySadist 's correct answer instead.

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