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anonymous

  • one year ago

What is the relative maximum and minimum of the function? f(x) = 2x^2 + 28x - 8 A. Minimum Value: -106 Range y > -106 B.Minimum Value: -7 Range y > -7 D.Minimum Value: 7 Range y > 7

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  1. anonymous
    • one year ago
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    @SolomonZelman

  2. anonymous
    • one year ago
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    \[f(x)=2x ^{2}+28x-8\]

  3. SolomonZelman
    • one year ago
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    minimum is the vertex in this case. (it doesn't have an abd max)

  4. anonymous
    • one year ago
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    how do i find the vertex? @SolomonZelman

  5. DecentNabeel
    • one year ago
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    A. Minimum Value: -106 Range y > -106

  6. anonymous
    • one year ago
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    how did you find that? I am just wondering so I can try and solve similar equations in the future @DecentNabeel

  7. DecentNabeel
    • one year ago
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    fist find the stationary.. \[\mathrm{Find\:the\:stationary\:points}:\quad x=-7\]

  8. DecentNabeel
    • one year ago
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    then find the.. \[\mathrm{Find\:the\:monotone\:intervals}\]

  9. DecentNabeel
    • one year ago
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    then.. \[\mathrm{Identify\:the\:extreme\:points}:\quad \mathrm{Minimum}\left(-7,\:-106\right)\]

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