iGreen
  • iGreen
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Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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iGreen
  • iGreen
What are the expected number of flights on time?
acxbox22
  • acxbox22
use proportions
mathstudent55
  • mathstudent55
Since 84% of the flights in the random sample are on time, we expect the same percentage to be on time in general. 84% means 84 out of 100.

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iGreen
  • iGreen
Whoa..major lag
mathstudent55
  • mathstudent55
\(\dfrac{84}{100} = \dfrac{x}{203} \)
Astrophysics
  • Astrophysics
Your fav igreen! XD
iGreen
  • iGreen
I came up with .84 * 203 or 170.52
Astrophysics
  • Astrophysics
That sounds right
mathstudent55
  • mathstudent55
You can think of the proportion as follows: 84 flights out of 100 are on time just like x flights out of 203 are on time.
Astrophysics
  • Astrophysics
170.52
iGreen
  • iGreen
I was trying to say that before anyone else commented..for some reason I can only make one comment and it glitches and I have to reload..
mathstudent55
  • mathstudent55
Correct. I'd round it off to 171 because I don't know what 0.52 of a flight is.
iGreen
  • iGreen
Okay, now it asks: "What is the standard deviation?"
iGreen
  • iGreen
Any idea on how to find that? @mathstudent55
iGreen
  • iGreen
What about you? @Astrophysics
Astrophysics
  • Astrophysics
Standard deviation is the average difference between any point of data and the mean, been a long time since I did statistics but I'm sure we can figure it out. \[\sigma = \sqrt{\frac{ 1 }{ N }\sum_{i=1}^{N}(x_i-\mu)^2}\]
Astrophysics
  • Astrophysics
But for this the easiest way I see is we can just use \[\sigma = \sqrt{npq}\] where \[\mu = \sqrt{np}\] that should be easy enough :P
iGreen
  • iGreen
Ahhh
iGreen
  • iGreen
I got 5.22
Astrophysics
  • Astrophysics
That sounds good!
iGreen
  • iGreen
\(\sf \sqrt{260 \times 0.84 \times 0.16}\)
iGreen
  • iGreen
Thanks!
Astrophysics
  • Astrophysics
Np

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