anonymous
  • anonymous
multiplying radicals. please help.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[(\sqrt{2}-\sqrt{-2}) (\sqrt{8}+\sqrt{-2})\]
anonymous
  • anonymous
Use the FOIL method just like (x+2)(x+2)
anonymous
  • anonymous
\[(\sqrt{2}-i \sqrt{2}) (2\sqrt{2}+i \sqrt{2})\] . . . \[(2\sqrt{2}+\sqrt{2})+i(2\sqrt{2}-2\sqrt{2})\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
i am stuck right there.. because in my mind the i part cancels out.. but i know it is wrong because thats not the answer in the book
anonymous
  • anonymous
\( (\sqrt{2}-\sqrt{-2}) (\sqrt{8}+\sqrt{-2}) \) FOIL F = First O = Outer I = Inner L = Last F \( (\sqrt{2})(\sqrt{8}) = \sqrt{16} = 4 \) O \( (\sqrt{2})(\sqrt{-2}) = 2i \) Do you see what I am doing here?
anonymous
  • anonymous
\( (\sqrt{2}-\sqrt{-2}) (\sqrt{8}+\sqrt{-2}) \) FOIL F = First O = Outer I = Inner L = Last F \( (\sqrt{2})(\sqrt{8}) = \sqrt{16} = 4 \) O \( (\sqrt{2})(\sqrt{-2}) = 2i \) I \( (-\sqrt{2})(\sqrt{-8}) = -4i \) L \( (-\sqrt{2})(\sqrt{-2}) = \sqrt{-4} = 2 \) Do you see what I am doing? Can you put the rest together? It is almost done.
anonymous
  • anonymous
And you left.....
anonymous
  • anonymous
sorry for the late response. it ll be 6-2i
anonymous
  • anonymous
thank you that makes more sense.
anonymous
  • anonymous
Good job correct!!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.