1. anonymous

$(\sqrt{2}-\sqrt{-2}) (\sqrt{8}+\sqrt{-2})$

2. anonymous

Use the FOIL method just like (x+2)(x+2)

3. anonymous

$(\sqrt{2}-i \sqrt{2}) (2\sqrt{2}+i \sqrt{2})$ . . . $(2\sqrt{2}+\sqrt{2})+i(2\sqrt{2}-2\sqrt{2})$

4. anonymous

i am stuck right there.. because in my mind the i part cancels out.. but i know it is wrong because thats not the answer in the book

5. anonymous

$$(\sqrt{2}-\sqrt{-2}) (\sqrt{8}+\sqrt{-2})$$ FOIL F = First O = Outer I = Inner L = Last F $$(\sqrt{2})(\sqrt{8}) = \sqrt{16} = 4$$ O $$(\sqrt{2})(\sqrt{-2}) = 2i$$ Do you see what I am doing here?

6. anonymous

$$(\sqrt{2}-\sqrt{-2}) (\sqrt{8}+\sqrt{-2})$$ FOIL F = First O = Outer I = Inner L = Last F $$(\sqrt{2})(\sqrt{8}) = \sqrt{16} = 4$$ O $$(\sqrt{2})(\sqrt{-2}) = 2i$$ I $$(-\sqrt{2})(\sqrt{-8}) = -4i$$ L $$(-\sqrt{2})(\sqrt{-2}) = \sqrt{-4} = 2$$ Do you see what I am doing? Can you put the rest together? It is almost done.

7. anonymous

And you left.....

8. anonymous

sorry for the late response. it ll be 6-2i

9. anonymous

thank you that makes more sense.

10. anonymous

Good job correct!!!