jhonyy9
  • jhonyy9
dear Champions ! give me please an explication - thank you - what is larger : A = 2^3^4 or B = 4^2^3 ? - how can i deciding that in case of A or in case of B the top exponent is an exponent of the bottom number ,in case A of 2 or in case B of 4 , or are exponent of the first exponent,in case A ,of 3 or in case B of 2 ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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jhonyy9
  • jhonyy9
Dear Champions this was what have surprised me in Brilliant.org ,math. forum when i have wrote for above exercise that are equal A and B - so this was a correct accepted answer but after this i have got a second exercise what was : (6x)^6 = 6^2^3 and for this equation i have wrote like firstly very easy root x=1 - so this was what have surprised me when have got the answer that x=1 is wrong so that not is root of this equation - i dont understand it why ? can somebody explaining me please ? thank you very much
jhonyy9
  • jhonyy9
- so than i remember right again the accepted correct root was x= 6^(1/3) - why ?
anonymous
  • anonymous
\(2^{3^4}\) or \((2^3)^4\)?

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anonymous
  • anonymous
if you mean \(2^{3^4}\) then consider \(4^{2^3}=2^{2\cdot2^3}=2^{2^4}\) so clearly \(2^{3^4}>2^{2^4}\) since \(3>2\implies 3^4>2^4\implies A=2^{3^4}>2^{2^4}=4^{2^3}=B\)
anonymous
  • anonymous
$$(6x)^6=6^{2^3}\\6^6 x^6=6^8\\x^6=6^2\\x^3=\pm6\\x=\pm\sqrt[3]{6}$$
dan815
  • dan815
|dw:1436490463980:dw|
dan815
  • dan815
|dw:1436490539513:dw|
dan815
  • dan815
perhaps trying to find a generalization for this is more intriguing
dan815
  • dan815
like does this hold for all consecutive numbers
dan815
  • dan815
|dw:1436490662853:dw|
anonymous
  • anonymous
the first one is exactly what I wrote; I don't understand why you just drew it out...

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